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Crank
3 years ago
14

Explain how sound travels from your vocal cords to your friend’s ear when you talk

Physics
1 answer:
AysviL [449]3 years ago
6 0

Answer:

Your vocal cords vibrate and then travel through the air to your friends ear. ... loudness is a humans perception of sound intensity, as intensity of a sound wave increases the loudness of a sound wave increases.

~+lil more info+~

Sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.

~+. can i get brainlist? :) .+~

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What can the vacuole hold? (check all that apply) <br> A) water<br> B) waste<br> C) nutrients (food)
Verizon [17]

Answer:

C & A 100000%

Explanation:

i took this test before and i just made sure on  safari . Its food (nutrients) and water

7 0
3 years ago
In the two-slit experiment, for the condition of bright fringes, the value of m = +2 corresponds to a path difference of λ.
melisa1 [442]

Answer:

False

Explanation:

We know that if path difference is even multiple of wavelength then bright fringes are formed and if path difference is odd multiple of wavelength then dark fringes are formed .

For bright fringes

Path difference Δx = m λ

m = 0 , 2 , 4 , 6.......

If m = 2 then the path difference will be

Δx = 2 λ

therefore the above statement if false.

False

7 0
3 years ago
Benjamin places a drop of purple food coloring in a cup of water. What can Benjamin expect to see? Explain the process that will
Dominik [7]
The drop of purple food dye will sink to the bottom while expanding around the cup turning the water purple
3 0
3 years ago
a rectangular block weighs 240N. The area of the block in contact with the floor is 20cm2 calculate the pressure on the floor
Romashka [77]

Answer:

The pressure on the floor is 12 Pascal(Pa).

Explanation:

Given,

Force (F) = 240N

Area (A) = 20 cm^2

Pressure (P) = ?

we know that,

P = F/A

= 240/ 20

= 12 Pa

8 0
3 years ago
Evaluate the gravitational potential energy between two 5.00-kg spherical steel balls separated by a center-tocenter distance of
navik [9.2K]

Answer:

U = 8.30×10-⁹J

Explanation:

m1 = m2 = 5.00kg masses of the spheres

d = 15.0cm = 15×10-²m

r = 5.10cm = 5.10×10-²m

R = d + r = 15×10-² + 5.10×10-²

R = 20.10 ×10-²m = 0.201m

G = 6.67×10-¹¹Nm²/kg²

U = Gm1×m2/R = potential energybetween the spheres

U = 6.67×10-¹¹×5.00×5.00/0.201

U = 8.30×10-⁹J

7 0
3 years ago
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