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Sav [38]
3 years ago
8

A circus performer walked up and to the right for a total displacement of 10\,\text m10m10, start text, m, end text along a diag

onal tightrope angled 30 \degree30°30, degree above the ground.
What was the vertical displacement of the circus performer in \text mmstart text, m, end text?
Physics
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

5m

Explanation:

khan academy

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B. its consist of waves of varying lengtu

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Metal sphere 1 has a positive charge of 7.00 nc . metal sphere 2, which is twice the diameter of sphere 1, is initially uncharge
MariettaO [177]

Answer:

2.33 nC, 4.67 nC

Explanation:

when the two spheres are connected through the wire, the total charge (Q=7.00 nC) re-distribute to the two sphere in such a way that the two spheres are at same potential:

V_1 = V_2 (1)

Keeping in mind the relationship between charge, voltage and capacitance:

C=\frac{Q}{V}

we can re-write (1) as

\frac{Q_1}{C_1}=\frac{Q_2}{C_2} (2)

where:

Q1, Q2 are the charges on the two spheres

C1, C2 are the capacitances of the two spheres

The capacitance of a sphere is given by

C=4 \pi \epsilon_0 R

where R is the radius of the sphere. Substituting this into (2), we find

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 R_2} (3)

we also know that sphere 2 has twice the diameter of sphere 1, so the radius of sphere 2 is twice the radius of sphere 1:

R_2 = 2R_1

So the eq.(3) becomes

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 2R_1}

And re-arranging it we find:

Q_2 = 2Q_1

And since we know that the total charge is

Q_1 + Q_2 = 7.00 nC

we find

Q_1 = 2.33 nC\\Q_2 = 4.67 nC

3 0
4 years ago
Current always returns to the:
Arlecino [84]

Current always returns to the negative terminal.

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8 0
4 years ago
Read 2 more answers
Can somebody explain it to me please?​
Volgvan

Answer:

45°.

It is a property of the parabolas.. When the angle between a parabola and the x-axis is 45° the range is maximum.

6 0
3 years ago
Read 2 more answers
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