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AlexFokin [52]
3 years ago
7

Evaluate the gravitational potential energy between two 5.00-kg spherical steel balls separated by a center-tocenter distance of

15.0 cm. (b) Assuming that they are both initially at rest relative to each other in deep space, use conservation of energy to find how fast will they be traveling upon impact. Each sphere has a radius of 5.10 cm.
Physics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

U = 8.30×10-⁹J

Explanation:

m1 = m2 = 5.00kg masses of the spheres

d = 15.0cm = 15×10-²m

r = 5.10cm = 5.10×10-²m

R = d + r = 15×10-² + 5.10×10-²

R = 20.10 ×10-²m = 0.201m

G = 6.67×10-¹¹Nm²/kg²

U = Gm1×m2/R = potential energybetween the spheres

U = 6.67×10-¹¹×5.00×5.00/0.201

U = 8.30×10-⁹J

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ivann1987 [24]

Question 7.

Given:

Mass, m = 2200 kg

Time, t = 8 s

Velocity = 12 m/s

Let's find the average net force required to stop the car.

To find the average net force required to stop the car, let's first find the acceleration of the car.

v=v_o+at

Where:

Initial velocity, vo = 12 m/s

Final velocity, v = 0 m/s (velocity of car when it stops)

t is the time = 8 seconds

a is the acceleration.

Rewrite the formula for a:

a=\frac{v-v_o}{t}

Hence, we have:

\begin{gathered} a=\frac{0-12}{8} \\  \\ a=\frac{-12}{8} \\  \\ a=-1.5m/s^2 \end{gathered}

The acceleration is -1.5 m/s² (negative because the car is deccelerating).

Now, to find the net force, we have:

\sum ^{}_{}F=ma

Where:

m is the mass = 2200 kg

a is the acceleration = -1.5 m/s²

Hence, we have:

\sum ^{}_{}F=2200\times(-1.5)=-3300\text{ N}

The negative sign indicates that the force acts in the opposite direction the car is travelling.

Therefore, average net force required to stop the car is 3300 Newtons in the opposite direction.

ANSWER:

3300 N in the opposite direction

8 0
1 year ago
a 5.00 × 105 kg rocket is accelerating straight up. Its engines produce 1.50 × 107 of thrust, and air resistance is 4.50 × 106 N
Angelina_Jolie [31]
This one is simple :)

use the equation F = ma and then re-arrange for a.

a = F / m

But there is a trick, so be careful. the question gives you wind resistance. Simply subtract the wind resistance from the thrust of the rocket to get the net force upward.

1.50 * 10^7N - 4.5 8 10^6N = 1.05 * 10^7N

So,

a =  \frac{F}{m} =  \frac{1.05*10^7N}{5.00*10^5kg}
3 0
4 years ago
If the sphere on the left is moved closer to the central cylinder and placed at a distance R/2 from the axis of rotation, what i
Alexxx [7]

Answer:

\alpha= \frac{2rF}{3mR}

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\tau = rF= I\alpha...............(1)

Total moment of inertia of masses and rod is

I=2m\left ( \frac{R}{2} \right )^2+mR^{2}

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\alpha= \frac{2rF}{3mR}

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4 years ago
Longitudinal waves cannot travel through a vacuum. True False
JulsSmile [24]
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A parallel plate capacitor fully charged to voltage V is connected to the battery (the voltage on the plates remains fixed). If
Papessa [141]

Charge will decreases.

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The capacitance of parallel plate capacitor with two plates of Area A separated by distance d and no dielectric material between plates is

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since from above equation it shows C is proportional to Q and also C is inversely proportional to distance d.

So, ATQ when d increases C will decrease which in result decreases charge on the capacitor.

Thus,  Charge will decrease.

Learn more about capacitance here:

     brainly.com/question/17115454

          #SPJ4

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