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Lilit [14]
3 years ago
10

The arrangement of elements in the Modern periodic table is based on their________

Chemistry
1 answer:
harina [27]3 years ago
6 0

Answer:

c

Explanation:

yan gonna HHAHHAAHHAHAHHHAHAHAHHA

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5. The rate constant for the reaction 3A  4B is 6.00 x 10-3 L•mol-1min-1. How long will it take the concentration of A to drop
valkas [14]

Answer:

it will take 444.44 min to reach 0.25 M from 0.75 M

Explanation:

since the reaction constant is k= 6.00*10⁻³ L*mol⁻¹min⁻¹. For a reaction rate of the form

-dCa/dt=k*Caⁿ

doing a dimensional analysis

[dCa/dt]=  mol/(L*min) =   [k]*[Caⁿ] = L/(mol*min) * (mol/L)ⁿ

then only n=2 can comply with the dimensional analysis, therefore we get a the second order reaction . Thus

-dCa/dt=k*Ca²

-dCa/Ca² =k*dt

-∫dCa/Ca² =k*∫dt

(1/Ca₂ - 1/Ca₁)= k*Δt

Δt= 1/k*(1/Ca₂ - 1/Ca₁)

replacing values

Δt= 1/k*(1/Ca₂ - 1/Ca₁) = 1/(6.00*10⁻³ L*mol⁻¹min⁻¹)*(1/0.25 M - 1/0.75 M)= 444.44 min

6 0
4 years ago
A 35.0-g piece of copper wire is heated, and the temperature of the wire changes from 29.0°C to 76.0C. The amount of heat absorb
kotykmax [81]

Answer:

0.15cal/g°C

Explanation:

Given parameters:

Mass of copper piece = 35g

Initial temperature = 29°C

Final temperature  = 76°C

Amount of heat absorbed  = 243cal

Unknown:

Specific heat of copper = ?

Solution:

The specific heat is the amount of heat supplied to a unit mass of substance that causes a 1°C rise in temperature.

   Specific heat C, = \frac{H}{m(T_{2} - T_{1}  )}

where H is the amount of heat supplied

           m is the mass of the copper

           T is the temperature

Input the parameters;

             C = \frac{243}{35(76 - 29)}   = 0.15cal/g°C

       

7 0
3 years ago
Purpose of boiling chip
vichka [17]
Your attempted answer is correct.
Indeed, certain liquids, including water, could superheat when heated in a perfectly smooth container.  The superheating could be interrupted by the minutest speck of dust or impurities causing a mass conversion into steam, observed physically as a bumping, causing splashes and endangering operators.  Boiling chips introduce these interruptions constantly and ensure a smooth boiling of the liquid.
4 0
3 years ago
________ is a type of root system.
Fiesta28 [93]
Answer: taproot explanation: a taproot is one of the three types of root systems plants have, along with fibrous and adventitious.
5 0
3 years ago
Read 2 more answers
Solid aluminum and gaseous oxygen react in a combination reaction to produce aluminum oxide: 4Al (s) + 3O2 (g) → 2Al2O3 (s) In
jek_recluse [69]

Answer: The percent yield of the reaction is 74 %

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

\text{Moles of aluminium}=\frac{2.5g}{27g/mol}=0.092mol

For oxygen gas:

\text{Moles of oxygen gas}=\frac{2.5g}{32g/mol}=0.078mol

The chemical equation for the reaction of titanium and chlorine gas follows:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

By Stoichiometry of the reaction:

4 moles of aluminium reacts with 3 moles of oxygen.

So, 0.092 moles of aluminium reacts with = \frac{3}{4}\times 0.092=0.069mol of oxygen

As, given amount of oxygen is more than the required amount. So, it is considered as an excess reagent.

Thus, aluminium is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of aluminium produce = 2 moles of Al_2O_3

So, 0.092 moles of aluminium will produce = \frac{2}{4}\times 0.092=0.046moles of Al_2O_3

Now, calculating the mass of aluminium oxide:

\text{Mass of aluminium oxide}=moles\times {\text {molar mas}}=0.046mol\times 102g/mol=4.7g

To calculate the percentage yield of titanium (IV) chloride, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield  = 3.5 g

Theoretical yield = 4.7 g

Putting values in above equation, we get:

\%\text{ yield of reaction}=\frac{3.5g}{4.7g}\times 100\\\\\% \text{yield of reaction}=74\%

Hence, the percent yield of the reaction is 74 %

6 0
3 years ago
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