A car travels 35 km west and 90 km north in two hours what is its average velocity?

1 answer:

8 0

Average velocity = Total Displacement / Total time taken

Total displacement is the distance from starting to end point.

35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.

So displacement = $\sqrt{35^2+90^2}$

= 96.56 km

So, Total displacement = 96.56 km

So, Average Velocity = 96.56 / 2 = 48.28 km/hr

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7. A force of 100 N acting on a body gives it a speed of 200 m/s in 2

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Answer:

Choice a. 1 kg, assuming that all other forces on the object (if any) are balanced.

Explanation:

By Newton's Second Law,

$\displaystyle a = \frac{\Sigma F}{m}$ ,

where

$a$ is the acceleration of the object in $\text{m}\cdot\text{s}^{-2}$ ,
$\Sigma F$ is the net force on the object in Newtons, and
$m$ is the mass of the object in kilograms.

As a result,

$\displaystyle m = \frac{\Sigma F}{a}$ .

Assume that all other forces on this object are balanced. The net force on the object will be $100\;\text{N}$ . The net force is constant. Acceleration should also be constant and the same as the average acceleration in the two seconds.