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3 years ago

A car travels 35 km west and 90 km north in two hours what is its average velocity?

1 answer:

8 0

Average velocity = Total Displacement / Total time taken

Total displacement is the distance from starting to end point.

35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.

So displacement = $\sqrt{35^2+90^2}$

= 96.56 km

So, Total displacement = 96.56 km

So, Average Velocity = 96.56 / 2 = 48.28 km/hr

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Why do people cry but dont say whats wrong they jus stand and act like we kno wha wrong

Finger [1]

Answer:

usually its because they dont wanna talk

Explanation:

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4 years ago

Determine the change in velocity of a car that start at rest and has a final velocity of 20 m/s north

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3 years ago

the net force on a vehicle is accelerating at a rate of 1.5 milliseconds is 1800 Newtons. What is the mass of the vehicles neare

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Answer:

The mass is 1200 kilograms

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3 years ago

A spherical drop of water carrying a charge of 43 pC has a potential of 540 V at its surface (with V = 0 at infinity). (a) What

almond37 [142]

Explanation:

Given that,

Charge on a spherical drop of water is 43 pC

The potential at its surface is 540 V

(a) The electric potential on the surface is given by :

$V=\dfrac{kq}{r}$

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(b) Let R is the radius of the spherical drop, when two such drops of the same charge and radius combine to form a single spherical drop. ATQ,

$\dfrac{4}{3}\pi r^3+\dfrac{4}{3}\pi r^3=\dfrac{4}{3}\pi R^3\\\\2r^3=R^3\\\\R=2^{1/3} r$

Now the charge on the new drop is 2q. New potential is given by :

$V=\dfrac{9\times 10^9\times 43\times 10^{-12}\times 2}{2^{1/3}\times 7.17\times 10^{-4}}\\\\V=856.79\ V$

Hence, the radius of the drop is $7.17\times 10^{-4}\ m$ and the potential at the surface of the new drop is 856.79 V.

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3 years ago

Consider two planets in space that gravitationally attract each other. if the masses of both planets are doubled, and the distan

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3 years ago

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