A car travels 35 km west and 90 km north in two hours what is its average velocity?
1 answer:
Average velocity = Total Displacement / Total time taken
Total displacement is the distance from starting to end point.
35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.
So displacement =
= 96.56 km
So, Total displacement = 96.56 km
So, Average Velocity = 96.56 / 2 = 48.28 km/hr
Total displacement is the distance from starting to end point.
35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.
So displacement =
= 96.56 km
So, Total displacement = 96.56 km
So, Average Velocity = 96.56 / 2 = 48.28 km/hr
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Answer:
Explanation:
The ant , at some point of time will be standing on the crest of moving wave passing under its feet . At that position the downward acceleration of the ant will be equal to its weight . Hence it will feel weightlessness . So at that time
Acceleration = g
Acceleration at the top position = ω²A where ω is angular velocity and A is amplitude of vibration ( transverse ) of crest .
ω =2 π n where n is frequency of transverse vibration of particles. This angular frequency will be equal to angular frequency of wave travelling on the rope .
frequency of travelling wave
n.=
ω =2 π x
ω² = 4π² x T/γ²μ}
For weightlessness
ω² A = g
A= g x γ²μ / 4π² T