a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how
long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175
s this is the time to fall from the top; it would take the same time to travel
upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175
= 0.35s
b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice
to solve this problem the time it takes to fall the final 0.13 m is: time it
takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to
fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it
takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m
is then twice this, or 0.08s
Answer:
53.5 N
Explanation:
Vertical component of the F force 50 sin30 = 25 N upward
force of gravity = m g = 8 * 9.81 =78.5 N Downward
NET downward force by block on table = net upward force exerted by table = 78.5 -25 =53.5 N
Answer:
1.13 mA
Explanation:
Length of wire L = 20.5 cm = 0.205m
Radius of wire r = 2.60/2 = 1.3cm = 0.0130m
Voltage V = 1 × 10³ V
Resistivity of pure silicon p = 2300 Ohms • m
Cross sectional area of the wire
A = pi × r² = pi × (0.013)² = 5.307 × 10 ^-4 m²
Resistance of the material
R = p• L/A
= 2300 • 0.205/5.307 × 10^-4 = 0.888 × 10⁶ Ohms
Using Ohms Law
R = V/ I
I = V/R
I = 10³/0.888 × 10⁶
= 0.001126 A
= 1.13 mA
By subtracting the value of absolute zero, also know as adding 273.15!
Given what we know, we can confirm that doubling the distance between you and a source of radiation decreases your exposure by 75%.
<h3>How is distance related to radiation exposure?</h3>
- As expected, increasing the distance from the source of the radiation will reduce its negative effects.
- Counter-intuitively however, doubling the distance does not reduce by half, but rather reduces its effects by 3/4th.
- This is due to the fact that the radiation effects from the source are inversely proportional to the square of the distance.
- This causes the changes to be far greater than expected.
Therefore, given that the radiation is proportional to the square of the distance, instead of being of a more direct relation, we can confirm that when doubling the distance between yourself and the source of the radiation, you can reduce its effects by 3/4 or 75%.
To learn more about radiation visit:
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