Answer:
The minimum possible coefficient of static friction between the tires and the ground is 0.64.
Explanation:
if the μ is the coefficient of static friction and R is radius of the curve and v is the speed of the car then, one thing we know is that along the curve, the frictional force, f will be equal to the centripedal force, Fc and this relation is :
Fc = f
m×(v^2)/(R) = μ×m×g
(v^2)/(R) = g×μ
μ = (v^2)/(R×g)
= ((25)^2)/((100)×(9.8))
= 0.64
Therefore, the minimum possible coefficient of static friction between the tires and the ground is 0.64.
The radius of the prop blade of an airplane is determined as 4.25 m.
<h3>
Radius of the prop blade</h3>
The radius of the prop blade of an airplane is calculated as follows;
a = v²/r
where;
- v is the linear speed
- r is the radius of the prop blade
- a is the centripetal acceleration
r = v²/a
r = (875²)/(180,000)
r = 4.25 m
Thus, the radius of the prop blade of an airplane is determined as 4.25 m.
Learn more about centripetal acceleration here: brainly.com/question/79801
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Answer:
v₁ = -0.8087 m / s
Explanation:
To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved
Initial instant. When they are united
p₀ = 0
Final moment. After throwing the brick
= (m_man + m_skate) v1 + m_brick v2
the moment is preserved
p₀ = p_{f}
0 = (m_man + m_skate) v₁ + m_brick v₂
v₁ = - 
the negative sign indicates that the two speeds are in the opposite direction
let's calculate
v₁ = - 
v₁ = -0.8087 m / s
Answer:
32
Explanation:
the atomic mass is the number of protons and neutrons in the nucleus of an atom
so we will add 16 + 16 = 32
