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Sphinxa [80]
2 years ago
13

What happens to the deflection when we increase the number of turns of wire

Physics
1 answer:
Katyanochek1 [597]2 years ago
4 0

Answer:

<u>Because the amount of the field is exactly related to the strength of the electric current, the deflection increases as the current increases. That is, as the electric current increases, so does the magnetic field.</u>

Explanation:

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No its false
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A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu
vredina [299]

Answer:

a) v_1=5.5172\ m.s^{-1}

b) v_2=-1.5152\ m.s^{-1}

c) v_3=4.6154\ m.s^{-1}

d) v_{avg}=3.8462\ m.s^{-1}

Explanation:

Given:

  • distance down the field in the first interval, d_1=16\ m
  • time duration of the first interval, t_1=2.9\ s
  • distance down the field in the second interval, d_2=-2.5\ m
  • time duration of the second interval, t_2=1.65\ s
  • distance down the field in the third interval, d_3=24\ m
  • time duration of the third interval, t_3=5.2\ s

a)

velocity in the first interval:

v_1=\frac{d_1}{t_1}

v_1=\frac{16}{2.9}

v_1=5.5172\ m.s^{-1}

b)

velocity in the second interval:

v_2=\frac{d_2}{t_2}

v_2=\frac{-2.5}{1.65}

v_2=-1.5152\ m.s^{-1}

c)

velocity in the third interval:

v_3=\frac{d_3}{t_3}

v_3=\frac{24}{5.2}

v_3=4.6154\ m.s^{-1}

d)

We know that the average velocity is given as the total displacement per unit time.

v_{avg}=\frac{d_1+d_2+d_3}{t_1+t_2+t_3}

v_{avg}=\frac{16-2.5+24}{2.9+1.65+5.2}

v_{avg}=3.8462\ m.s^{-1}

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3 years ago
What is needed to give a larger boulder a large acceleration?
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More force needs to be applied
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4 years ago
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How can parallax allow us to determine the distance to a star
tensa zangetsu [6.8K]

Answer:

Astronomers use a method similar to the one you used with your homemade quadrant. Twice the distance to the Sun, divided by the distance to the star (which is unknown so far) is equal to the tangent of the parallax angle of the star.

4 0
4 years ago
A source emits monochromatic light of wavelength 495 nm in air. when the light passes through a liquid, its wavelength reduces t
Katyanochek1 [597]
By definition, the refractive index is
n = c/v
where c =  3 x 10⁸ m/s,  the speed of light in vacuum
v = the speed of light in the medium (the liquid).

The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz

Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m, 
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s

The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406

Answer:  a.  1.14
6 0
3 years ago
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