Ask question

Ask question

All categories

3 years ago

7

How is your day today?

2 answers:

aleksley [76]3 years ago

5 0

Answer:

kul and yours hope it was great

Delvig [45]3 years ago

4 0

Answer:

nice

Explanation:

You might be interested in

The Thermite reaction reacts iron (III) oxide, Fe2O3 with aluminium powder, Al, to form aluminium oxide, Al2O3 and iron, Fe. Fe2

Rama09 [41]

So, I don't know the answer for b but I think I found the answer for a.

I sincerely hope this isn't wrong

3 0

2 years ago

How many moles are in 25kg of Fe2O3?

expeople1 [14]

Answer:

The answer is 159.6882.

Assuming you are converting between grams Fe2O3 and mole.

3 0

3 years ago

A chemist fills a reaction vessel with 9.20 atm nitrogen monoxide (NO) gas, 9.15 atm chlorine (CI) gas, and 7.70 atm nitrosyl ch

ivanzaharov [21]

Answer:

The reactions free energy $\Delta G = -49.36 kJ$

Explanation:

From the question we are told that

The pressure of (NO) is $P_{NO} = 9.20 \ atm$

The pressure of (Cl) gas is $P_{Cl} = 9.15 \ atm$

The pressure of nitrosly chloride (NOCl) is $P_{(NOCl)} = 7.70 \ atm$

The reaction is

$2NO_{(g)} + Cl_2 (g)$ ⇆ $2 NOCl_{(g)}$

From the reaction we can mathematically evaluate the $\Delta G^o$ (Standard state free energy ) as

$\Delta G^o = 2 \Delta G^o _{NOCl} - \Delta G^o _{Cl_2} - 2 \Delta G^o _{NO}$

The Standard state free energy for NO is constant with a value

$\Delta G^o _{NO} = 86.55 kJ/mol$

The Standard state free energy for $Cl_2$ is constant with a value

$\Delta G^o _{Cl_2} = 0kJ/mol$

The Standard state free energy for $NOCl$ is constant with a value

$\Delta G^o _{NOCl} =66.1kJ/mol$

Now substituting this into the equation

$\Delta G^o = 2 * 66.1 - 0 - 2 * 87.6$

$= -43 kJ/mol$

The pressure constant is evaluated as

$Q = \frac{Pressure \ of \ product }{ Pressure \ of \ reactant }$

Substituting values

$Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}$

$= 0.0765$

The free energy for this reaction is evaluated as

$\Delta G = \Delta G^o + RT ln Q$

Where R is gas constant with a value of $R = 8.314 J / K \cdot mol$

T is temperature in K with a given value of $T = 25+273 = 298 K$

Substituting value

$\Delta G = -43 *10^{3} + 8.314 *298 * ln [0.0765]$

$= -43-6.36$

$\Delta G = -49.36 kJ$

4 0

3 years ago

How many mL are 2.3 mol of CO2 at STP?

kupik [55]

Answer:

0.052mL

Explanation:

1mole of a gas occupy 22.4L.

Therefore, 1 mole of CO2 will also occupy 22.4L.

If 1mole of CO2 occupies 22.4L,

Then 2.3moles of CO2 will occupy = 2.3 x 22.4 = 51.52L

coverting this volume to mL, we simply divide by 1000 as shown below:

51.52/1000 = 0.05152mL = 0.052mL

8 0

3 years ago

Read 2 more answers

Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?

Mariulka [41]

Volume=V=3L
Pressure=P=814mmHg
Temp=T=25°C

So

No of moles=n

$\\ \rm\rightarrowtail PV=nRT$

$\\ \rm\rightarrowtail n=\dfrac{PV}{RT}$

$\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}$

$\\ \rm\rightarrowtail n=2442/25R$

$\\ \rm\rightarrowtail n=97.7Rmol$

5 0

2 years ago