Total mass = x
It would be: x*32.38/100 = 32
x = 3200/32.38 = 97.56
Atomic mass of (OH)2 = 34
So, remaining mass = 97.56-34 = 63.56
which is approximately equal to mass of copper
So, we can say m is copper here, and formula of the compound would be Cu(OH)2
Answer:
1) The correct step in the scientific method that Victor did is Construct a hypothesis.
2) Given mass and density, volume is calculated as mass divided by density.
Explanation:
1) Before doing the assay and make a graph with the results obtained, Victor should think what he wants to prove, so he should make a hypoythesis to test with the assay.
2) The formula of density is
density = mass/volume ⇒ density x volume = mass ⇒ volume = mass/density.
Answer:
Explanation:
general expression for the ionization energy of any one-electron species.
= z² x ground level energy / n²
z is atomic no , n is energy level .
ground level energy of
H = 1.31 x 10³ kJ/mol
He⁺ = 2² x 1.31 x 10³ kJ/mol = 5.24 x 10³ kJ/mol
Li²⁺ = 3² x 1.31 x 10³ kJ/mol = 1.18 x 10⁴ kJ/mol
b ) the ionization energy of B⁴⁺.
= 5² x 1.31 x 10³ kJ/mol = 32.75 x 10³ kJ/mol
c ) minimum energy required to remove the electron from the n = 3 level of He⁺ per mole
= 5.24 x 10³ / 9 kJ/mol
= 5.82 x 10² kJ/mol
= 5.82 x 10² x 10³ / 6.02 x 10²³ J
.9667 X 10⁻¹⁸ J
= .9667 X 10⁻¹⁸ / 1.6 X 10⁻¹⁹ eV
= 6.042 eV
= 1237.5 / 6.042
= 204.82 nm
=
d )
Answer:
Explanation:
<u>1) Data:</u>
Base: NaOH
Vb = 15.00 ml = 15.00 / 1,000 liter
Mb = ?
Acid: H₂SO₄
Va = 17.88 ml = 17.88 / 1,000 liter
Ma = 0.1053
<u>2) Chemical reaction:</u>
The <em>titration</em> is an acid-base (neutralization) reaction to yield a salt and water:
- Acid + Base → Salt + Water
- H₂SO₄ (aq) + NaOH(aq) → Na₂SO₄ (aq) + H₂O (l)
<u>3) Balanced chemical equation:</u>
- H₂SO₄ (aq) + 2 NaOH(aq) → Na₂SO₄ (aq) + 2H₂O (l)
Placing coefficient 2 in front of NaOH and H₂O balances the equation
<u>4) Stoichiometric mole ratio:</u>
The coefficients of the balanced chemical equation show that 1 mole of H₂SO₄ react with 2 moles of NaOH. Hence, the mole ratio is:
- 1 mole H₂SO₄ : 2 mole NaOH
<u>5) Calculations:</u>
a) Molarity formula: M = n / V (in liter)
⇒ n = M × V
b) Nunber of moles of acid:
- nₐ = Ma × Va = 0.1053 (17.88 / 1,000)
c) Number of moles of base, nb:
- nb = Mb × Vb = Mb × (15.00 / 1,000)
d) At equivalence point number of moles of acid = number of moles of base
- 0.1053 × (17.88 / 1,000) = Mb × (15.00 / 1,000)
- Mb = 0.1053 × 17.88 / 15.00 = 0.1255 mole/liter = 0.1255 M
Answer: Odor of ammonia would we detect first on the other side of the room.
Explanation:
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:
Thus the odor of ammonia would we detect first on the other side of the room as the rate of effusion of ammonia would be faster as it has low molecular weight as compared to hydrogen sulphide.
