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irina1246 [14]
2 years ago
11

Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?

Chemistry
1 answer:
Mariulka [41]2 years ago
5 0
  • Volume=V=3L
  • Pressure=P=814mmHg
  • Temp=T=25°C

So

No of moles=n

\\ \rm\rightarrowtail PV=nRT

\\ \rm\rightarrowtail n=\dfrac{PV}{RT}

\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}

\\ \rm\rightarrowtail n=2442/25R

\\ \rm\rightarrowtail n=97.7Rmol

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If a 250mL beaker weighs 13.473g and the same beaker plus 2.2 mL of water weighs 15.346g. How much does the 2.2 mL of water, alo
Sindrei [870]

Given :

A 250 ml beaker weighs 13.473 g .

The same beaker plus 2.2 ml of water weighs 15.346 g.

To Find :

How much does the 2.2 ml of water, alone, weigh .

Solution :

Now, mass of water is given by :

\text{Mass of water alone = Total mass - Mass of beaker alone}\\\\Mass =15.346-13.473\ g\\\\Mass =1.873\ g

Therefore , mass of 2.2 ml of water alone is 1.873 g .

Hence , this is the required solution .

4 0
3 years ago
Boron<br> B<br> 10.811<br> Number of neutrons
andrew-mc [135]

Answer:

6

Explanation:

To determine the number of neutrons we round 10.8 to 11 and subtract the atomic number (5) and get 6; therefore, boron has 6 neutrons.

7 0
3 years ago
You have a gas with a density of 4.8 grams per Liter and a molar mass of 75.3 grams per mole. How many liters of gas do you have
Andre45 [30]

d = √((x1 - x2)2 + (y1 - y2)2)  

( -2 , 5 )   ( 12 , -1 )    

  ↑    ↑         ↑     ↑      

 x1    y1        x2    y2  

d = √((-2 - 12)2 + (5 - (-1))2) = √((-14)2 + 62) = √(196 + 36) = √232 = 2√58 ≈ 15.23

7 0
3 years ago
What are all four Quantum numbers of 11th electron of magnesium​
ruslelena [56]

Answer:n=0

l=0

ml=0

ms = =1/2 or +1/2

Explanation:

3 0
3 years ago
If a 45.6 g piece of aluminum has a density of 2.1 g/mL, what volume would it have?
Mashcka [7]

Answer:

\boxed {\tt 21.7142857 \ mL}

Explanation:

The density formula is:

d=\frac{m}{v}

Rearrange this formula for v, volume. Multiply by v, then divide by d.

d*v=\frac{m}{v}

d*v=m

\frac{d*v}{d} =\frac{m}{d}

v=\frac{m}{d}

Volume can be found by dividing the mass by the density. The mass of the aluminum is 45.6 grams and the density is 2.1 grams per milliliter.

v=\frac{45.6 \ g }{ 2.1 \ g/mL}

Divide. Note the grams, or g, will cancel out.

v=\frac{45.6 }{2.1 \ g}

v= 21.7142857 \ mL

The volume of the aluminum is 21.7142857 milliliters.

3 0
3 years ago
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