Question

Kathy dropped a snowball from a building that is 39.2 meters tall. The equation t2 = 39.29.8 represents the amount of time, in seconds, it takes for the snowball to reach the ground. How long did it take the snowball to reach the ground?

Answer 1

Answer:

We note that the equation that is compatible with the given equation is the kinematic equation of free fall where;

t² = 39.2 × 2/9.81

From which we have;

The time it takes the snowball to reach the ground is approximately 2.83 seconds

Step-by-step explanation:

The height of the building from which the ball is dropped, h = 39.2 m

The equation of the dropped a snowball, is given as follows;

t² = 39.2 × 9.8

Using the From the equation of free fall, we have;

s = u·t + 1/2·g·t²

Where;

u = The initial velocity = 0 m/s

t = The time of flight

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we get;

∴ s = The height from which the snowball is dropped = 39.2 m

Therefore, we get;

39.2 = 0×t + 1/2×9.81×t²

∴ t² = 39.2 × 2/9.81  ≈ 7.99

t = √(7.99) ≈ 2.83

The time it takes the snowball to reach the ground, t ≈ 2.83 s.