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svet-max [94.6K]
2 years ago
10

Kathy dropped a snowball from a building that is 39.2 meters tall. The equation t2 = 39.29.8 represents the amount of time, in s

econds, it takes for the snowball to reach the ground. How long did it take the snowball to reach the ground?
Mathematics
1 answer:
DIA [1.3K]2 years ago
8 0

Answer:

We note that the equation that is compatible with the given equation is the kinematic equation of free fall where;

t² = 39.2 × 2/9.81

From which we have;

The time it takes the snowball to reach the ground is approximately 2.83 seconds

Step-by-step explanation:

The height of the building from which the ball is dropped, h = 39.2 m

The equation of the dropped a snowball, is given as follows;

t² = 39.2 × 9.8

Using the From the equation of free fall, we have;

s = u·t + 1/2·g·t²

Where;

u = The initial velocity = 0 m/s

t = The time of flight

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we get;

∴ s = The height from which the snowball is dropped = 39.2 m

Therefore, we get;

39.2 = 0×t + 1/2×9.81×t²

∴ t² = 39.2 × 2/9.81  ≈ 7.99

t = √(7.99) ≈ 2.83

The time it takes the snowball to reach the ground, t ≈ 2.83 s.

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3 years ago
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Step-by-step explanation:

2 eggs are pink

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3 years ago
Help me with this question, please!
AURORKA [14]

Answer:

3,432 m²

Step-by-step explanation:

The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)

Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)

✔️Surface area of ½-cylinder = ½[2πr(h + r)]

r = ½(0.4) = 0.2 m

h = 0.6 m

π = 3.14

Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]

= 0.628(0.8)

Surface area of ½-cylinder = 0.5024 m²

✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)

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H = 0.55 m

Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)

Surface area of rectangular box = 1.58 m²

✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²

✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)

= 0.5024 + 1.34

= 1.8424

Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912

= 3,432 m²

8 0
3 years ago
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kvv77 [185]

Answer:

<u>Use Pythagorean theorem:</u>

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#8

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3 0
3 years ago
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