Proovethat √2+√3 is irrational

Mathematics

1 answer:

algol133 years ago

8 0

Answer:

If √2 + √3 was rational then its square, i.e. 5+2√6 would be too. Hence √6 would be rational as well. But we know that the square root of an integer is either an integer or is irrational. Hence √6 isn't rational, a contradiction to the hypothesis.

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Someone PLS help me with this math problem and please explain to show how you got the answer tysm to anyone who can help me!!!

Vesnalui [34]

Answer:

3 grams

Step-by-step explanation:

square=2g x 6=12g

cricle= 3g x 3= 9g

12+9=21 grams +2triangles

2nd chain:

cricle= 3g x 2 = 6g

square= 2g x 3=6g

6 +6=12g + 5triangles

21 + 2t = 12 + 5t

9 + 2t = 5t

9 = 3t

3=t

triangle = 3g

5 0

3 years ago

A researcher studied the radioactivity of asbestos. She sampled 81 boards of asbestos, and found a sample mean of 193.2 bips, an

Ksivusya [100]

Answer:

a) Confidence interval is (182.86,203.54).

b) (i) Yes, 200 bips is a true mean as it lie in the interval.

(ii) No, 210 bips is not a true mean as it doesn't lie in the interval.

Step-by-step explanation:

Given : A researcher studied the radioactivity of asbestos. She sampled 81 boards of asbestos, and found a sample mean of 193.2 bips, and a sample standard deviation of 49.5 bips.

To find : (a) Obtain the 94% confidence interval for the mean radioactivity. (b) (i) According the interval that you got, is 200 bips a plausible value for the true mean? (ii) What about 210 bips?

Solution :

a) The confidence interval formula is given by,

$\bar{x}-z\times \frac{\sigma}{\sqrt{n}}$