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3 years ago

Djamil stands under a waterfall that is 75 feet tall. The distance of the of waterfall with respect to its time is:

Mathematics

1 answer:

laiz [17]3 years ago

6 0

Answer:

=77 and the reserve is to get the answers

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Which movement most influenced the Founding Fathers? A the Enlightenment B the French Revolution C the Age of Exploration D the

Naddika [18.5K]

Answer is A it’s the most important one

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3 years ago

what is "The temperature outside at 6 a.m. is 4 degrees celsius. The temperature rising by 1.5 degrees celsius every hour." in a

LiRa [457]

Answer:

7 a.m is 5.5

Step-by-step explanation:

(6=4)+1.5=(_+1.5)

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3 years ago

Which of the following represents the additive inverse of 125? A. -(-125) B. 125 C. -125 D. 1/25

Elden [556K]

Additive inverse of 125 is – 125, option C is correct.

Solution:

Given that , a number is 125

We have to find the additive inverse for the above given number from the above given set of options.

Now, we know that, sum of a number and its additive inverse equals to 0.

So, let us check option by option.

Option A:

Given number is -(-125)

-(-125) ⇒ 125 + ( - ( - 125 ) )

⇒ 125 + 125

⇒ 250 ⇒ wrong option

Option B:

Given number is 125

⇒ 125 + 125 ⇒ 250 ⇒ wrong option

Option C:

Given number is -125

125 + ( - 125 ) ⇒ 125 – 125 ⇒ 0 ⇒ correct option

Hence, additive inverse of 125 is – 125, option C is correct

7 0

4 years ago

Read 2 more answers

.. Which of the following are the coordinates of the vertices of the following square with sides of length a?

atroni [7]

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Step-by-step explanation:

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

To find the sides of a square, let us use the distance formula,

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,a), T(a,a), W(a,0)$ has sides of length a.

Option B: $O(0,0), S(0,a), T(2a,2a), W(a,0)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

This is not a square because the lengths are not equal.

Option C: $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$ has sides of length 2a.

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

Thus, the square with vertices $O(0,0), S(a,0), T(a,a), W(0,a)$ has sides of length a.

Thus, the correct answers are option a and option d.

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3 years ago

In how many ways can four people sit in a car for a road trip if only two of them can drive?

ElenaW [278]

They can sit 4 different ways

8 0

3 years ago

Read 2 more answers