Using Hooke's law, F subscript s p r i n g end subscript equals k increment x, find the elastic constant of a spring that stretc
2 answers:
Let's rewrite Hook's law:
where
F is the force
k is the spring's constant
x is the compression/elongation of the spring
Neglecting the sign (since we are not interested in the direction of the force), we can re-arrange the formula and use the data of the problem to find the spring constant:
Therefore, the correct answer is B) 2 N/cm.
where
F is the force
k is the spring's constant
x is the compression/elongation of the spring
Neglecting the sign (since we are not interested in the direction of the force), we can re-arrange the formula and use the data of the problem to find the spring constant:
Therefore, the correct answer is B) 2 N/cm.
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Answer:
T1 = 490.5 [N], T2 = 490.5[N]
Explanation:
First, we must draw a free body diagram of the steel ball hanging and the two wires holding it as well as the angle forming the wires between them.
The free-body diagram can be seen in the attached image.
As the cables are symmetrical with respect to the vertical axis, the force in cables 1 and 2 is equal, so when performing a force sum equal to zero on the Y-axis, we can find the force value of any cable.
The solution of the equations can be seen in the attached image
