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muminat
4 years ago
6

Some unpolarized light has an intensity of 1375 W/m2 before passing through three polarizing filters. The transmission axis of t

he first filter is vertical. The second filter's transmission axis is 31.0° from vertical. The third filter's transmission axis is 41.0° from vertical. What is the intensity of the light that emerges from the three filters?
Physics
1 answer:
chubhunter [2.5K]4 years ago
4 0

Answer:

intensity of the light that emerges from the three filters is 560.80 W/m²

Explanation:

Given data

intensity  I = 1375 W/m2

angle 1 = 31.0°

angle 2  = 41.0°

to find out

intensity of the light that emerges from the three filters

solution

we know intensity of light pass 1st polarize = I/2 = 1375 / 2 = 687.5  W/m2

so intensity after 2nd polarize pass = I 1st cos²(θ)

I 2nd = 687.5 cos²(31) = 687.5 ( 0.836754)  = 575.27 W/m2

and

intensity after 3rd polarize pass = I 2nd cos²(θ)

I 3rd = 575.27 cos²(41) = 575.27 (0.974839) = 560.80 W/m2

so that intensity of the light that emerges from the three filters is 560.80 W/m²

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<u>I had to search the Figure on Google to solve this question.</u>

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Explanation:

<u>I had to search the Figure on Google to solve this question.</u>

a) We can find the force of the third person as follows:

\Sigma F_{x} = F_{1x} + F_{2x} + F_{3x} = 0

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So, in x-direction we have:

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In y-direction we have:

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To find the direction of F₃ we need to calculate its angle with respect to the y-direction (in the third quadrant):

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<em>b) If the third person exerts the force found in part (a) the car will stop, so the only way for the cart to accelerate at 200 m/s² is that the third person does not exert the force found in a. </em>      

<u>To find the weight of the cart​ when it accelerates at 200 m/s², we need to consider: F₃ = 0</u>.  

First, we need to find the cart's mass. Since the car is moving in the x-direction we have:

\Sigma F_{x} = F_{1x} + F_{2x} = ma

45 N*cos(70) + 75 N*cos(20) = m*200 m/s^{2}

m = \frac{45 N*cos(70) + 75 N*cos(20)}{200 m/s^{2}} = 0.43 kg

Now, the weight of the cart​ is:

P = mg = 0.43 kg*9.81 m/s^{2} = 4.22 N

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