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slega [8]
3 years ago
9

Suppose a skydiver (mass = 80kg) is falling toward the Earth. Calculate the skydiver’s gravitational potential energy at a point

when the skydiver is 100m above the Earth.
Physics
1 answer:
Vlad [161]3 years ago
4 0
Ep is gravitational potential energy
m is mass (kg)
g is gravitational field strength (N/kg)
h is height (m)

Ep= mgh
= 80kg*9.8N/kg*100m
= 78 400 J
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I don’t have a question because I posted a photoz
Scorpion4ik [409]

Part a:

Q_{1} = 56

Q_{2} = 60

Q_{3} = 63

     The quartiles are found by finding the medium of the data, and then the mediums of the two different data sets on either side of the medium. The Q_{2} is the overall medium, Q_{1} is the medium of the first half, and Q_{3} is the medium of the second half.

-> How is the medium found? When finding the medium we put the values in order least to greatest and pick the middle value.

[] See attached

Part b:

The range is 7.

The interquartile range is the range of numbers between Q_{1} and Q_{3}. In other words, it is 50% of the data, directly in the middle.

This becomes 63 - 56 = 7

Part c:

79 is an outlier.

It is an outlier because it is 1.5 above or below (in this case, above) the interquartile range.

-> 63 + (7 + \frac{7}{2}) ≤ 79

-> 63 + 10.5 ≤ 79

-> 73.5 ≤ 79

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

7 0
1 year ago
What does more damage; a slow semi truck, or a fast sports car
Goshia [24]
The fast sports car does more damage then the slow semi truck
7 0
2 years ago
A scientist is studying the effect on human health of bacteria that live in the human intestine. In her study, she found that th
irga5000 [103]
70 is the correct awnser
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The gravitational self potential energy of a solid ball of mass density ρ and radius R is E. What is the gravitational self pote
Alenkasestr [34]
It will be
E = mgh.
where h and g are constant thus
m can be written as 4/3πr^3*density
E = 4/3πr^3* density
E? = 4/3π(2R)^3* density
= 4/3π8r^3
thus the e will be 4/3π8r^3* density/4/3πr^3*density nd thus you get 8E ..
8 0
2 years ago
What temperature increase is necessary to increase the power radiated from an object by a factor of 8?
Aleks04 [339]

To solve this problem it is necessary to apply the concepts related to the Power defined from the Stefan-Boltzmann equations.

The power can be determined as:

P = \sigma T^4

Making the relationship for two states we have to

\frac{P_1}{P_2} = \frac{T_1^4}{T_2^4}

Since the final power is 8 times the initial power then

P_2 = 8P_1

Substituting,

\frac{1}{8} = \frac{T_1^4}{T_2^4}

T_2 = T_1 8*(\frac{1}{4})

T_2 = 1,68T_1

The temperature increase would then be subject to

\Delta T = T_2-T_1

\Delta T = 1.68T_1 -T_1

\Delta T = 0.68T_1

The correct option is D, about 68%

7 0
2 years ago
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