Answer:
3.5
Step-by-step explanation:
500 x 7
3500/1000
3.5
All you have to do is follow PEMDAS (if you don't know what that is, search it up).
-2-5(4n-6)=-132
Distribute the 5 to everything in the parentheses.
-2-20n+30= -132
Combine like terms.
-20n+28 = -132
Subtract 28 from both sides.
-20n = -160
Divide by -20 on both sides.
n = 8
Common difference = 2nd term - first term
= -13-(-6)
= -13+6
= -7
We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.
</span>we have that
<span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3
radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2
A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>
By the divergence theorem, the surface integral taken over
,
is equivalent to the triple integral of the divergence of
over
, the space bounded
,
We have
The latter integral is then given by
