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vichka [17]
3 years ago
9

Chloe is trying to find three consecutive, positive integers such that six times the largest is equal to the twice sum of the tw

o smaller integers. Show that the three consecutive, positive integers 4, 5, and 6 are not the ones Chloe is looking for.
Mathematics
1 answer:
andrezito [222]3 years ago
6 0

Answer:

The three consecutive numbers cannot be 4, 5, and 6 because, the result will be 36 ≠ 18, which is indeterminate

Step-by-step explanation:

The given parameters are;

The three consecutive positive numbers Chloe is trying to find are x, x+1, x + 2

The conditions of the three positive numbers are;

6 × (x + 2) = 2 × (x + x + 1)

We check if the three consecutive numbers can be 4, 5, and 6 by substituting the values as follows;

x + 2 = 6

x + 1 = 5

x = 4

Which gives;

6 × (6) ≠ 2 × (4 + 5)

36 ≠ 18

Therefore, the three consecutive numbers cannot be 4, 5, and 6

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It is given
vekshin1

Answer:

  • (C) DF=4 cm, ∠A=80⁰

Step-by-step explanation:

<h3>Question </h3>
  • It is given the ∆ABC≅∆FDE and AB=4 cm, ∠B=40⁰ and ∠E=60⁰, then which of the following is true.
  • (A) DE=4cm, ∠A=80⁰
  • (B) DE=4 cm, ∠C=80⁰
  • (C) DF=4 cm, ∠A=80⁰
  • (D) DF=4cm, ∠C=80⁰​
<h3>Solution</h3>

<u>Corresponding sides and angles are:</u>

  • AB ≅ FD
  • ∠A≅∠F, ∠B≅∠D, ∠C≅∠E

<u>Given</u>:

  • AB = 4 cm, so FD = 4 cm
  • ∠B = 40⁰ and ∠E = 60⁰, so  ∠D = 40⁰ and ∠C = 60⁰

and

  • ∠A = ∠F = 180⁰​ - (40⁰​ + 60⁰​) = 80⁰​

Considering all above we see that correct answer option is (C) ​

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