The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
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(6)^-2 Is equivalent to 1/36
The first statement and the second statement are FALSE.
In mathematics, a function<span> is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. An example is the </span>function<span> that relates each real number x to its square x</span>2<span>.
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Using the formula S = ut +1/2at²
S=h= 20ft, u = 2ft/s, and a = 10m/s²
Thus; 20 =2t + 20t²
Therefore; 20t²+2t-20=0
Solving the equation quadratically for the value of t,
we get; t = 1.057 or t=-1.182
But t can not be negative,
Therefore, t= 1.1 seconds (to the nearest tenth)
