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3 years ago

Can someone help me answer this question X= 6 6 6 6

Mathematics

2 answers:

OverLord2011 [107]3 years ago

5 0

Answer:

Would it be 90 degrees?

Step-by-step explanation:

kobusy [5.1K]3 years ago

4 0

Answer:

X=1296

or if your trying to look for the area it would be x=1111

its basically length times width

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Answer the question in the picture

7nadin3 [17]

Answer:

10²

Step-by-step explanation:

left triangle = 2 × 2 = 4 ÷ 2 = 2²

right triangle = 2 × 4 = 8 8 ÷ 2 = 4²

middle square = 2 × 2 = 4²

2 + 4 + 4 = 10²

7 0

3 years ago

You are in a bike race. When you get to the first checkpoint, you are $\frac{2}{5}$

Black_prince [1.1K]

Answer:

The distance from the star to the second checkpoint is 4 miles

Step-by-step explanation:

The complete question in the attached figure

we know that

When you get to the second checkpoint, you are 1/4 of the distance to the finish

The distance from the star to the second checkpoint is equal to the total distance multiplied by 1/4

The total distance is 40 miles ( see the attached figure)

The distance from the star to the second checkpoint is

$\frac{1}{4}(40)=10\ miles$

<em>Find out the distance from the start to the first checkpoint</em>

Multiply the distance from the star to the second checkpoint by 2/5

$\frac{2}{5}(10)=4\ miles$

6 0

3 years ago

Reasoning A salesperson's commission rate is 6%. What is the commission from the sale of

ANTONII [103]

Answer:

1980

Step-by-step explanation:

It’s right, trust me

5 0

3 years ago

Find sec 2Theta in exact value

forsale [732]

Answer:

$sec(2\theta)=-\frac{5}{4}$

Step-by-step explanation:

we know that

step 1

Find $cos(\theta)$

we know that

$tan^2(\theta)+1=sec^2(\theta)$

we have

$tan(\theta)=3$

substitute

$3^2+1=sec^2(\theta)$

$sec^2(\theta)=10$

$sec(\theta)=\pm\sqrt{10}$

Remember that

Angle theta lie in Quadrant I

$sec(\theta)$ is positive

$sec(\theta)=\sqrt{10}$

Remember that

$sec(\theta)=\frac{1}{cos(\theta)}$

therefore

$cos(\theta)=\frac{1}{\sqrt{10}}$

step 2

Find $sin(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin(\theta)=tan(\theta)cos(\theta)$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

$tan(\theta)=3$

substitute

$sin(\theta)=(3)(\frac{1}{\sqrt{10}})$

$sin(\theta)=\frac{3}{\sqrt{10}}$

step 3

Find $cos(2\theta)$

we know that

$cos(2\theta)=2cos^2(\theta)-1$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

substitute

$cos(2\theta)=2(\frac{1}{\sqrt{10}})^2-1$

$cos(2\theta)=\frac{1}{5}-1$

$cos(2\theta)=-\frac{4}{5}$

Remember that

$sec(2\theta)=\frac{1}{cos(2\theta)}$

therefore

$sec(2\theta)=-\frac{5}{4}$

8 0

3 years ago

Louann and Carla received equal scores on a test made up of multiple choice questions and an essay. Louann got 14 multiple choic

defon

Each multiple choice question was worth 5 points.

14x+24 = 16x +14
2x = 10
x = 5

4 0

3 years ago

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