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Anastasy [175]
3 years ago
15

What is the equation of the line that began with a y-intercept of (0,4), was shifted up 3 units, and is perpendicular to y = 3/4

x-2?
answer choices:

A. y=-4/3x+7

B. y=-3/4x+7

C. y=-3/4x+4

D. y=-4/3x+4
Mathematics
1 answer:
timama [110]3 years ago
7 0

Answer:

Option A

y=-4/3x+7

Step-by-step explanation:

To solve this, we need to understand the various components of the equation of a straight line.

A straight line has the equation: y =mx + c

<em>m</em> is the slope and<em> c</em> is the intercept on the y-axis. If we can get these two components, we can figure out the equation for the new line.

Calculating the slope, <em>m</em>

To obtain the slope of the new line, we use the fact that it is perpendicular to the slope of the line y = 3/4x-2.

This means that

3/4 X <em>m</em> = -1

<em>m</em> = -4/3

To obtain the intercept, <em>c</em>

The intercept can be obtained by adding 3 to the y-component of (0, 4).

This will give (0, 7). Hence the intercept c will be 7.

Therefore, the equation of the line will be y = -4/3x+7. Option A

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