Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.
Let x be the number of $2 increases in price, then the revenue from renting cars is given by

.
Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by

Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
</span><span>

For maximum profit, the differentiation of the profit function equals zero.
i.e.
</span><span>

The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.
Therefore, the </span><span>rental charge will maximize profit is $64.</span>
The correct answer is 9/14
Answer:
75 dollars
Step-by-step explanation:
If an item is 50 and you want to markup 50%, you must find 50% of 50 to find how much the item will go up by from 50.
So 50% of 50 means 50% times 50.
50%=.5 or 1/2
So .5(50)=25.
The item is going up by 25 dollars.
So we started at 50 dollars.
So 50+25 is going to be the new amount.
50+25=75 is the new amount.
Answer:
D. None of the choices are correct.
Step-by-step explanation:
If <em>B</em> is the midpoint of AC, then that means that AB is congruent to BC. Because this is true, you can set 8x + 4 and 10x - 8 equal.
8x + 4 = 10x - 8
Now just solve for x. Subtract 8x from both sides and add 8 to both sides.
4 = 2x - 8
12 = 2x
Then divide by 2.
6 = x
Another way to do this problem is to set up the same equation, but instead of solving it, plug in answer choices A, B, and C independently of each other. Then simplify to see if those are right. You'll find out that none of them are.
If

is the amount of salt in the tank at time

, then the rate at which this amount changes over time is given by the ODE


We're told that the tank initially starts with no salt in the water, so

.
Multiply both sides by an integrating factor,

:




Since

, we have

so that the amount of salt in the tank over time is given by

After 10 minutes, the amount of salt in the tank is