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Mars2501 [29]
3 years ago
8

Y=x/4+1/2 find the x and y Pls help asap

Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

y = 1/4x + 1/2 and x = -2 +4y

Step-by-step explanation:

Solving it in a way that x/4 is a fraction and not division so you would make that 1/4x. y = x/4 +1/2 x/4 is 1/4x so then you subtract 1/2 from both sides to get y - 1/2 = 1/4x. You can then divide 1/4 on both sides. -1/2 divided by 1/4 is -2 and 1/4y. This will get your answer of x = 1/4y -2 for x. Y is just 1/4x + 1/2

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OleMash [197]
In highest poer of placholder is  1 then it is linear

1/3x^1-2y^1=7
it is linear
yes it is
8 0
2 years ago
Sasha places an online order. In addition to the price of the item she orders, she pays 5% tax and a flat shipping fee of $15. T
natita [175]

Answer:

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Let the price is x.

<u>Set the equation and solve for x:</u>

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8 0
3 years ago
Read 2 more answers
Delilah finds her answer is 90, but she copied the expression incorrectly from the board. If her reasoning and answer for the ex
USPshnik [31]

Question:

Three students were working on 630,000÷700 in math class.

a. Desiree finds the quotient is 9,000 and Micah finds the quotient is 900.

    Determine which student found the correct quotient.

b. Delilah finds her answer is 90, but she copied the expression incorrectly from the board. If her reasoning and answer for the expression she copied are correct, what expression might she have written?

Answer:

a. Micah is correct

b.

Expression = 63000 \div 700

Expression = 630000 \div 7000

Step-by-step explanation:

Given

Expression = 630000 \div 700

Desiree = 9000

Micah = 900

Solving (a): Who is correct?

To do this, we first calculate the quotient of the expression.

Expression = 630000 \div 700

Divide 630000 by 700

Quotient = 900

Hence:

Micah is correct

Solving (b): What Delilah must have copied?

We have:

Delilah = 90

There are no options to pick from. So, we just need to work out expressions that equals 0.

Possible expressions are:

Expression = 63000 \div 700

Expression = 630000 \div 7000

3 0
3 years ago
Question 9 of 10
sleet_krkn [62]

Answer:

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8 0
3 years ago
Is the sum of an irrational number and rational number always irrational?
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It can be proved by contradiction.

Let:
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b - an irrational number
c - the sum of a and b

a+b=c

Let assume that c is a rational number. Then a and c can be expressed as fractions with integer numerator and denominator:
a=\dfrac{d}{e}\\&#10;c=\dfrac{f}{g}\\      where d,e,f,g \in \mathbb{Z}

\dfrac{d}{e}+b=\dfrac{f}{g}\\&#10;b=\dfrac{f}{g}-\dfrac{d}{e}\\&#10;b=\dfrac{ef}{eg}-\dfrac{dg}{eg}\\&#10;b=\dfrac{ef-dg}{eg}

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8 0
3 years ago
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