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2 years ago

5.

1 answer:

7 0

Well, the formula for the perimeter of a rectangle is:
2l + 2w.
So, by plugging in our values of the length and width, we can easily find an answer:
length = L
width = 1 + L ( 1/3 )
2 ( L ) + 2 ( L ( 1/3 + 1 ) = 42
2l + 2/3( L ) + 2 = 42
8/3 ( L ) = 40
L = 40 * 3/8
L = 15
Therefore, the length is 15 and the width is 6.

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Graph the linear equation x-3y=-6

TEA [102]

Answer:

Step-by-step explanation:

One of the easier approaches to graphing a linear equation such as this one is to solve it for y, which gives us both the slope of the line and the y-intercept.

x-3y=-6 → -3y = -x - 6, or 3y = x + 6.

Dividing both sides by 3, we get y = (1/3)x + 2.

So the slope of this line is 1/3 and the y-intercept is 2.

Plot a dot at (0, 2). This is the y-intercept. Now move your pencil point from that dot 3 spaces to the right and then 1 space up. Draw a line thru these two dots. End.

Alternatively, you could use the intercept method. We have already found that the y-intercept is (0, 2). To find the x-intercept, let y = 0. Then x = -6, and the x-intercept is (-6, 0).

Plot both (0, 2) and (-6, 0) and draw a line thru these points. Same graph.

7 0

3 years ago

Read 2 more answers

K is the midpoint of PQ, P has

Pachacha [2.7K]

Answer:

Coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q $(x_2,y_2)$

We will use the formula of midpoint: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We are given midpoint K and $x_1,y_1$ the coordinates of P we need to find $x_2,y_2$ the coordinates of Q.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\$

Now, we can write

$-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16$

So, we get coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

6 0

2 years ago

What is the length of side s of the square shown below?

AnnZ [28]

Answer:

Step-by-step explanation:

Using the properties of 45-45-90 triangles

8=x*sqrt(2)

4sqrt(2)=x

6 0

2 years ago

Suppose angles A and B are complementary angles and m∠A = (x-5)° and m∠B = (2x+20)° Solve for X and then find m∠A and m∠B

MariettaO [177]

The angles are x =25, angle A = 20 and B = 70

<h3>How to solve for the angles?</h3>

The given parameters are:

A = x - 5

B = 2x + 20

Both angles are complementary angles.

This means that:

x - 5 + 2x + 20 = 90

Evaluate the like terms

3x = 75

Divide both sides by 3

x = 25

Substitute x = 25 in A = x - 5 and B = 2x + 20

A = 25 - 5 = 20

B = 2 * 25 + 20 = 70

Hence, the angles are x =25, angle A = 20 and B = 70

Read more about complementary angles at:

brainly.com/question/98924

#SPJ1

3 0

1 year ago

Find the area between the two functions

Inga [223]

The area between the two functions is 0

<h3>How to determine the area?</h3>

The functions are given as:

f₁(x)= 1

f₂(x) = |x - 2|

x ∈ [0, 4]

The area between the functions is

A = ∫[f₂(x) - f₁(x) ] dx

The above integral becomes

A = ∫|x - 2| - 1 dx (0 to 4)

When the above is integrated, we have:

A = [(|x - 2|(x - 2))/2 - x] (0 to 4)

Expand the above integral

A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]

This gives

A = [2 - 4] - [-2- 0]

Evaluate the expression

A = 0

Hence, the area between the two functions is 0