Answer:
4*x^4*y^22
Step-by-step explanation:
Your goal here is to REDUCE the given expression to simplest terms.
One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as: (2x^2*y^8)*y^2*(2x^2*y^10)^2.
Dividing this rewritten expression by 2x^2*y^8 results in:
y^2(2x^2*y^10)^2.
We now need to raise (2x^2*y^10) to the power 2. Doing this, we get:
4x^4*y^20.
Multiply this by y^2 (see above):
y^2*4x^4*y^20
The first factor is 4: 4y^2*x^4*y^20. This is followed by the product of y^2 and y^20: 4*y^22*x^4
Finally, this should be re-written as
4*x^4*y^22
Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:
8*x^6*y^30 4*x^4*y^22
----------------- = ------------------ = 4*x^4*y^22
2x^2y^8 1
150 is your correct answer
Answer:
The GCF of 7 and 12 is 1.
Answer:
Step-by-step explanation:
Midpoints of two coordinates is expressed using the formula;
M(X, Y) = (x2+x1/2, y2+y1/2)
Given the coordinates c(5,3) and d(-3,-6)
x1 = 5, y1 = 3, x2 = -3 and y2 = -6
X = x1+x2/2
X = 5+(-3)/3
X = 5-3/2
X = 2/2
X = 1
Also;
Y = y1+y2/2
Y = 3+(-6)/2
Y = 3-6/2
Y = -3/2
Y = -1.5
