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2 years ago

-2(b-5)=16 x when b is 3 is

Mathematics

1 answer:

Kitty [74]2 years ago

3 0

Answer:

When B is 3, it is not answerable. The sides are not equal, if it were -3 the answer would be 16.

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How much can 14 go into 16

Fantom [35]

Once, 14 divided by 16 equals 1 with a remainder of 2

4 0

3 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

2 years ago

Is -5 a solution to the equation 6x +5 = 5x + 8 + 2x? Explain.

MrRa [10]

Answer:

No -5 is not the solution, But x =-3 is the solution.

Step-by-step explanation:

Given:

$6x+5= 5x+8+2x$

We need to find the solution for above equation we get;

Solution:

Now when we put the value of x =-5 we get

$6x+5 =5x+8+2x\\\\6\times-5+5 = 5\times-5+8+2\times-5\\\\-30+5 = -25+8-10\\\\-25\neq -27$

hence -5 is not the Solution for given equation.

On Solving the above equation we get;

$6x+5 =7x+8$

Now Combining the like terms we get;

$7x-6x =5-8$

Now Using Subtraction property we get;

$x = -3$

Hence The solution to equation is -3.

6 0

2 years ago

Find the mean and the mean average height.

-BARSIC- [3]

Answer:

a.) $mean=200.3$

b.) $210$ $cm$

Step-by-step explanation:

a.) We are given the heights and their frequency. We can make a new set:

198, 199, 199, 199, 200, 200, 201, 201, 201, 201, 201, 202, 202

Now find the mean. The mean is found by adding all the numbers in the set, then dividing the total by the number of terms in the set. Add:

$198+199+199+199+200+200+201+201+201+201+201+202+202=2604$

Now count the terms. There are 13 terms. Divide the total by the number of terms:

$\frac{2604}{13}= 200.3$

The mean is 200.3.

b.) Use random values like 200, 198 etc. and add them to the total of the last set, then divide by 14 instead of 13 (because there is a new player). Do this until you get a mean of 201 with the new height:

$2604+210=2814\\\\\frac{2814}{14}= 201$

For the new mean to be 201 cm, the new player has a height of 210 cm.

Finito.

8 0

2 years ago

If 2/3 of the 600 seeds sprouted, how many seeds did not sprout?

kupik [55]

Answer:

200 seeds

Step-by-step explanation:

If 2/3 of the seeds sprouted, then (1-2/3) 1/3 of the seeds did not sprout.

1/3 * 600 = 600/3 = 200

200 seeds did not sprout

8 0

2 years ago