Answer:
The rate of the boat in still water is 40 miles per hour
The rate of the current is 10 miles per hour
Step-by-step explanation:
we know that
The speed or rate is equal to divide the distance by the time
Let
x ----> the rate of the current (miles per hour)
y ----> the rate of the boat in still water (miles per hour)
we have that
<em>going upstream </em>
----> equation A
<em>going downstream </em>
----> equation B
Solve the system of equations by elimination
Adds equation A and equation B
<em>Find the value of x </em>
therefore
The rate of the boat in still water is 40 miles per hour
The rate of the current is 10 miles per hour
Answer:
600
Step-by-step explanation:
cus
Remember that transformation between Cartesian and polar system are:
x=r*cos(α)
y=r*sin(α)
From this we can conclude that:
r=√(x^2 + y^2)
Using trigonometry transformations we can write:
r=sin(2α) = 2sin(α)cos(α)
Now we can multiply both sides with r^2:
r^3 = 2(r*sin(α))*(r*cos(α))
Now using some replacements we can write:
(x^2 + y^2)^(3/2) = 2*x*y
Answer:
B
Step-by-step explanation:
16 x 3/2 = 24
24 x 3/2 = 36
36 x 3/2 = 54
Answer:
L=21.6in and w=13.6
Step-by-step explanation:
If the length is 8 inches longer than its width, we can write the width as "w" and the length as the width w+ 8
Area is (width)(Length) = (width)(width+8)
W
----------
| |
| |
| | L = w+8
| |
| |
-----------
A = (w+8)(w)
A = w2 + 8w = 295.
(Problem states that area is 295 sq in)
Need to solve this quadratic equation
w2 +8y - 295 = 0
Factor:
(w - 13.64) (w + 21.64) = 0
So
w - 13.64 = 0. or. w + 21.64= 0
Solve these and get
w = 13.64. or. w = -21.64
Only one that makes sense in real life is the poitive one.
So the dimensions are
Width = 13.64 inches
Length = 21.64 inches
