0.65, or in fraction form 65/100
<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
Answer:
Yes
Step-by-step explanation:
The formula for area of a triangle is A = (1/2)bh,
For the first triangle we can leave it in general terms, so it's area is
A = (1/2)bh, depending on what b and h are, but it doesn't matter here...
The second triangle has base that is twice the other triangles base. Bases being multiples of each other is the definition of being proportional so the bases are proportional, an the area of the second triangle is
A = (1/2)(2b)h, which simplifies to
A = bh
Comparing the 2 areas, you can see that one has a multiplier of (1/2), so their areas are proportional
Answer:
1. B) Figure B.
2. C) Figure C.
3. D) Figure D.
4. C) Figure C.
Step-by-step explanation:
Given: Radius of Circle A= 4
Radius of Circle B= 5
Radius of circle C= 6
Radius of circle D= 7
Now, finding circumference and area of all the circle.
We know, circumference of circle= 
Area of circle= 
Where, r= radius of circle and π = 3.14
First, solving for figure A
Circumference= 
Area= 
Solving for Figure B
Circumference= 
Area= 
Solving for Figure C
Circumference= 
Area= 
Solving for Figure D
Circumference= 
Area= 
∴ 1. Answer is Figure B.
2. Answer is figure C.
3. Answer is Figure D
4. Answer is Figure C.
