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3 years ago

1. Find the slope of the line that goes through the points (2, 5) and (6, 7)

Mathematics

1 answer:

ella [17]3 years ago

7 0

Answer:

$\displaystyle m = \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Slope Formula: $\displaystyle m = \frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Identify

Point (2, 5)

Point (6, 7)

Step 2: Find slope m

Substitute in points [Slope Formula]: $\displaystyle m = \frac{7-5}{6-2}$
[Fraction] Subtract: $\displaystyle m = \frac{2}{4}$
[Fraction] Simplify: $\displaystyle m = \frac{1}{2}$

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Give one example of when you would make a frequency table to solve the problem

RideAnS [48]

Answer:

Consider a class in which there are 40 students .There is a Mathematics test of 50 marks .Two students were absent.The Duration of test was for one and half an hour.

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So in this case it would be better to prepare frequency polygon by selecting a class interval.

Class interval = 0-5,5-10,10-15,15-20,20-25,25-30,30-35,35-40,40-45,45-50.

Or 0-10,10-20,20-30,30-40,40-50.

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3 years ago

A car travels at a speed of s miles per hour. It covers 126 miles in 3 hours.

makvit [3.9K]

Answer:

s=42

Step-by-step explanation: 126 divided by 3 = 42

42mph

8 0

2 years ago

Learn with an example

Marta_Voda [28]

Answer:

y = 9x + (-7) should be the answer

6 0

3 years ago

The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?

vovikov84 [41]

Answer:

The first term is:

$a_1=-61$

Step-by-step explanation:

The arithmetic sequence is defined by

$a_n=a_1+\left(n-1\right)d$

where

$a_1$ is the first term

$d$ is the common difference

the 17th term of an arithmetic sequence is 51.

i.e. $a_{17}=51$

$a_n=a_1+\left(n-1\right)d$

$a_{17}=a_1+\left(17-1\right)d$

$51=a_1+\left(17-1\right)7$ ∵ $n = 17$ , $a_{17}=51$ , $d=7$

$a_1+112=51$ ∵ $\left(17-1\right)\cdot \:\:7=112$

$a_1=-61$

Therefore, the first term is:

$a_1=-61$

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3 years ago

The endpoints of a line segment graphed on a Cartesian coordinate system are (4, 1) and (-2, -4). What are the coordinates of th

Masja [62]

The midpoint of (x1,y1) and (x2,y2) is $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

just average them

(4,1) and (-2,4)
the midpoint is $(\frac{4-2}{2},\frac{1-4}{2})=(\frac{2}{2},\frac{-3}{2})=$ (1,-1.5)

5 0

3 years ago

Read 2 more answers