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3 years ago

Write an express for the perimeter of the figure shown by combing like terms.

Mathematics

1 answer:

bogdanovich [222]3 years ago

8 0

Answer:

30c + 6 i believe

Step-by-step explanation:

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EXAMPLE 2 Prove that 9ex is equal to the sum of its Maclaurin series. SOLUTION If f(x) = 9ex, then f (n + 1)(x) = for all n. If

amm1812

Answer:

To Prove: $9e^x$ is equal to the sum of its Maclaurin series.

Step-by-step explanation:

If $f(x) = 9e^x$ , then $f ^{(n + 1)(x)} =9e^x$ for all n. If d is any positive number and |x| ≤ d, then $|f^{(n + 1)(x)}| = 9e^x\leq 9e^d.$

So Taylor's Inequality, with a = 0 and M = $9e^d$ , says that $|R_n(x)| \leq \dfrac{9e^d}{(n+1)!} |x|^{n + 1} \:for\: |x| \leq d.$

Notice that the same constant $M = 9e^d$ works for every value of n.

But, since $lim_{n\to\infty}\dfrac{x^n}{n!} =0 $ for every real number x$$ ,

We have $lim_{n\to\infty} \dfrac{9e^d}{(n+1)!} |x|^{n + 1} =9e^d lim_{n\to\infty} \dfrac{|x|^{n + 1}}{(n+1)!} =0$

It follows from the Squeeze Theorem that $lim_{n\to\infty} |R_n(x)|=0$ and therefore $lim_{n\to\infty} R_n(x)=0$ for all values of x.

$THEOREM\\If f(x)=T_n(x)+R_n(x), $where $T_n $is the nth degree Taylor Polynomial of f at a and $ lim_{n\to\infty} R_n(x)=0 \: for \: |x-a|$

By this theorem above, $9e^x$ is equal to the sum of its Maclaurin series, that is,

$9e^x=\sum_{n=0}^{\infty}\frac{9x^n}{n!}$ for all x.

6 0

3 years ago

What is the interquartile range of the following data set 2, 5, 9, 11, 18,30, 42, 55, 58, 73, 81

In-s [12.5K]

Answer:

4.2/5. 4.

Step-by-step explanation:

4 0

4 years ago

Can someone help please?!?! Quickly

Yanka [14]

Part 1) Finding x

Note the double tickmarks for segments XY and YZ. This indicates the segments are the same length, which leads to point Y being the midpoint of segment XZ.

Therefore, XZ is twice as long as XY

XZ = 2*( XY )

XZ = 2*( 2x-1 )

XZ = 4x - 2

We also know that XZ = 2(3x-4) = 6x-8. Let's equate 4x-2 and 6x-8 and solve for x

6x-8 = 4x-2

6x-4x = -2+8

2x = 6

x = 6/3

x = 3

<h3>Answer is 3</h3>

=====================================

Part 2) Finding the length of YZ

The resut of part 1 (x = 3) is plugged into the equation for XY to get

XY = 2*x-1

XY = 2*3-1

XY = 6-1

XY = 5

Segment XY is 5 units long. So is segment YZ as these two segments are the same length (aka congruent).

<h3>Answer: 5</h3>

=====================================

Part 3) Finding the length of segment XZ

The answer from the previous part was 5. This doules to 5*2 = 10

-----

A longer way to get the same answer is to plug x = 3 into the XZ equation and we get...

XZ = 2*(3x-4)

XZ = 2*(3*3-4)

XZ = 2*(9-4)

XZ = 2*5

XZ = 10

and we get the same answer

<h3>Answer: 10</h3>

5 0

4 years ago

What is the total surface area of a right rectangular prism with a base of 2 cm by 3 cm and a height of 6 cm? A) 13 cm2. B) 72 c

Stolb23 [73]

(L · W · 2) + (perimeter of the base · height). For this prism, that's (2 cm · 3 cm · 2) + (2 cm + 2 cm + 3 cm + 3 cm) · 6 cm. This is (12 cm2) + (10 cm · 6 cm) = <span>72 cm2.</span>

3 0

3 years ago

Read 2 more answers

haley spent 1/2 of an hour playing on her phone. that used up 3/8 of her battery. how long would she have to play on her phone t

bonufazy [111]

She would need to play 50 minutes more to waste all her battery. In total 80 minutes.

6 0

3 years ago