1.
Han Solo genotype: ff
Offspring genotypes: Ff, ff
There is a 50% chance the child will have the force.
2.
Let f be webbed feet and F be non-webbed feet
Parental genotypes: ff ; FF
Possibility of webbed feet in offspring: 0%
3.
Yes, it is possible if both parents are heterozygous. 25% of offspring will be grey.
4.
Pheonotypes: Hairy and non-hairy fur
genotypes: HH, Hh, hh
5.
Parental genotypes: RR and RL
Offspring phenotypes: Brown hair and Brown and Black hair
Offspring genotypes: RR, RL
6.
Genotypes: BW
Phenotypes: Grey
7.
Black
8.
None of his children will be bald.<span />
Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
<u>Explanation:</u>
Note, Telangana is known to be an area whose climate is usually semi-arid, that is, it is an area that is dry and receives some small amount of rain.
Thus, plants in the Telangana region would usually possess the following adaptive features;
- ability to survive under extreme heat
- growing longer roots than normal in other to find water in the soil
- efficient water conservation especially in their stems.
Cancer is basically a disease of uncontrolled cell division.
