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Darya [45]
3 years ago
11

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics
1 answer:
Doss [256]3 years ago
4 0

Answer: b would be: 59.

Step-by-step explanation:

180-60= 120

120-61= 59

hope this helped <3

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Y=-1\2+1 with a slope intercept that contains (5,6)
Semenov [28]

Answer:

y - 1/2x + 7/2

Step-by-step explanation:

y = 1/2x + 1

6 = 1/2 (5) + b

6 = 5/2 + b

7/2 = b

8 0
3 years ago
Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h
irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = <u><em>population proportion.</em></u>

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, H_0 : p = 0.70      {means that the population proportion is equal to 0.70}

Alternate Hypothesis, H_A : p < 0.70      {means that the population proportion is less than 0.70}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                           T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion = 0.63

            n = sample of observations = 100

So, <u><em>the test statistics</em></u>  =  \frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }

                                     =  -1.528

The value of z-test statistics is -1.528.

<u>Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.</u>

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

4 0
3 years ago
Write a function to represent each problem situation Carmen deposits $1000into simple interest account.The rate for the account
kolezko [41]

The function the represent the balance in the account as a function of time t is p(t) = 1000 + 40t

<h3><u>Solution:</u></h3>

Given that,

Carmen deposits $1000 into simple interest account

The rate for the account is 4%

To find: function the represent the balance in the account as a function of time t

Given is simple interest account

The formula for simple interest is given as:

S.I = \frac{ prt}{100}

Where, "p" is the principal and "r" is the rate of interest and "t" is the number of years

In simple interest,

total amount after "t" years = principal + simple interest

Here in this question, Carmen deposits $1000

p_0 = 1000

r = 4 \% = \frac{4}{100} = 0.04

Thus we can frame a function as:

total amount after "t" years = principal + simple interest

p(t) = p_0 + (p_0 \times r \times t )

p(t) = 1000 + (1000 \times 0.04)t\\\\p(t) = 1000 + 40t

Where, p(t) is the amount after "t" years and p_0 is the principal sum

Thus the function is obtained

7 0
3 years ago
What is the answer for e
Flauer [41]
-4 is the correct answer
5 0
3 years ago
If a/b = 4/3 and b/c = 2/3, what is a,b, and c?
kaheart [24]

Answer:

.

Step-by-step explanation:

\frac{a}{b}  =  \frac{4}{3}

\frac{b}{c}  =  \frac{2}{3}

to give b from both equation the same value

\frac{a}{b}  =  \frac{4}{3}  \times   \frac{2}{2}  =  \frac{8}{6}

\frac{b}{c}  =  \frac{2}{3}  \times  \frac{3}{3}  =  \frac{6}{9}

a:b:c = 8:6:9

a = 8

b = 6

c = 9

7 0
3 years ago
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