A.Determine whether –(x3 + 5x + 1) is equivalent to x3 + 5x + 1. b.Determine whether (–x)3 + 5(–x) + 1 is equivalent to x3 + 5x + 1.
c. Determine whether –x3 + 5x + 1 is equivalent to –(x3 + 5x + 1).
d. Determine whether (–x)3 + 5(–x) + 1 is equivalent to –(x3 + 5x + 1)
A function is even if f(x) = f(-x) for all x.
f(-x) = -x³ + 5(-x) + 1
f(-x) = -x³ - 5x + 1
b.Determine whether (–x)3 + 5(–x) + 1 is equivalent to x3 + 5x + 1.
A = 6
tn = a + (n - 1)d
t4 = 6 + 3d = 12
3d = 12 - 6 = 6
d = 6/3 = 2
f(n + 1) = f(n) + 2
Answer:
answer
x = -13/ 15, 0
Step-by-step explanation:
15x^2 + 13 x = 0
or, x(15x + 13) = 0
either, x = 0
or, 15x + 13 = 0
x = -13/15
I think k divided by 2 so D.
