Answer:
20.11% of oxygen
Explanation:
The reaction is:
2CuO ⇒ 2Cu + O2
If you have an initial amoung of a sample, thi may be have impurities, so you have to start from products to know what you had at the begining.
to make a relation between reagents and products you need to change the mass to mol, then you can relate them with the molar ratio.
Now you have the initial amount of oxygen, to convert to percent you must divide the mass of oxygen between the mass of the sample and multiply by 100
Answer:
tensile strength, elongation, flexural strength, and impact resistance.
Explanation:
Answer:
8.912x10^-18
Explanation:
-dn/dt = pANa/2piMRT
100 g = initial copper
Number of moles = 100/63.546
= 1.5736
Mass of copper left = 100-10.0168
= 89.9832
Moles = 89.9832/63.546
= 1.4160
dn = 1.4160-1.5736
= -0.1576
dt = 2 hrs
A = 3.23mm² = 3.23x10^-6
M = 63.546
T = 0.0821
T = 1508k
Na = 6.023x10²³
When we insert all these into the formula above
We get
P = 8.912x10^-18atm
Answer:
Its A.) Polymers are macromolecules
Explanation:
Answer:
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