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olchik [2.2K]
3 years ago
11

The arrows show the changes of state.

Chemistry
1 answer:
Romashka [77]3 years ago
3 0

Answer:

condensation

Explanation:

when gases change to liqud it condenses.This occurs when the temperature is lowered

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How many liters are in 62.9 g NaOH?
Sunny_sXe [5.5K]

Answer:

39.99711 grams.

Explanation:

Moles to Grams Naoh

1 mole is equal to 1 moles NaOH, or 39.99711 grams.

5 0
2 years ago
In one kind of nuclear reaction, two nuclei fuse, or join together, to form a larger nucleus. This kind of reaction happens only
Vladimir79 [104]
High pressures are necessary to create such reaction so that the particles will be able to overcome electrostatic repulsion. The particles that make up a particular atom are covered by shells of energy that react to different impulses like pressure. When particles are exposed to extreme environmental pressure it has the tendency to split its particles and undergo nuclear fusion successfully.
7 0
3 years ago
After 4 half-lives 10 grams of uranium remains. How much uranium did you start with?
Free_Kalibri [48]

Answer:

i think 40 grams

Explanation:

4 0
3 years ago
A certain element forms an ion with 36 electrons and a charge of +2. identify the element. express your answer as a chemical sym
blsea [12.9K]

The element is Sr (strontium)

strontium is in atomic number 38 in the periodic table. Strontium has 2.8.8.8.8.2

it loses two electrons to become  stable hence it has a charge of   2+. when strontium loses two electron it form ion with 36 electrons

6 0
3 years ago
The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2.
harkovskaia [24]

Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.

Solution:- The balanced equation for the combustion of acetylene is:

2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)

From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.

35.0molC_2H_2(\frac{4molCO_2}{2molC_2H_2})

= 70molCO_2

The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.

From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.

35.0molC_2H_2(\frac{5molO_2}{2molC_2H_2})

= 87.5molO_2

Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.

So, the theoretical yield should be calculated using 84.0 moles of oxygen as:

84.0molO_2(\frac{4molO_2}{5molO_2})

= 67.2molCO_2

7 0
3 years ago
Read 2 more answers
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