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3 years ago

BRAINLIEST!!!!!!! LOTS OF POINTS!!!!!!

Chemistry

1 answer:

devlian [24]3 years ago

3 0

Answer:

What do you mean lots of points its only 8 points?

Explanation:

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The length of a covalent bond depends upon the size of the atoms and the bond order.

lukranit [14]

Answer:

True

Explanation:

The length of covalent bond depends upon the size of atoms and the bond order.

6 0

2 years ago

The molar heat of vaporization of water is 40.7 kJ mol . How much heat must be absorbed to convert 50.0 grams of liquid water at

podryga [215]

Molar mass of water 18g/mol

Number of mols = 50.0g/18g/mol =2.78 mol

Heat absorbed = 40.7 kj/mol * 2.78 mol = 113.1 kj.

8 0

3 years ago

An ideal gas sample is confined to 3.0 L and kept at 27 °C. If the temperature is raised to 77 °C and the initial pressure was 1

Nadusha1986 [10]

The gas is confined in 3.0 L container ( rigid container) ⇒ the volume remains constant when the temperature is increased from from 27oC to 77oC and therefore V1=V2 .

<h2>Hope it helps you please mark as brainlist</h2>

6 0

2 years ago

What kind of bond is the result of the transfer of an electron?

serious [3.7K]

Answer:

Answer choice A

Explanation:

When an electron is transferred to another atom, both atoms involved become ions.

5 0

3 years ago

Read 2 more answers

Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. How many grams of di

pychu [463]

Answer:

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant. Explanation:

$Ca(NO_3)_2(aq)+2NH_4F(aq)\rightarrow CaF_2(aq)+2N_2O(g)+4H_2O(g)$

Moles of calcium nitrate = $\frac{31.3 g}{164 g/mol}=0.1908 mol$

Moles of ammonium fluoride = $\frac{38.7 g}{37 g/mol}=1.046 mol$

According to reaction , 2 moles of ammonium fluoride reacts with 1 mole of calcium nitrate.

Then 1.046 moles of ammonium fluoride will react with :

$\frac{1}{2}\times 1.046 mol=0.523 mol$ calcium nitarte .

This means that ammonium fluoride is in excess amount and calcium nitrate is in limiting amount.

Hence, calcium nitrate is a limiting reactant.

So, amount of dinitrogen monoxide will depend upon moles of calcium nitrate.

So, according to reaction , 1 mole of calcium nitarte gives 2 moles of dinitrogen monoxide gas .

Then 0.1908 moles of calcium nitrate will give:

$\frac{2}{1}\times 0.1908 mol=0.3816 mol$ of dinitrogen monoxide gas.

Mass of 0.03816 moles of dinitrogen monoxide gas:

0.03816 mol × 44 g/mol = 16.79 g

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant.

8 0

2 years ago