Question

If 4.00 moles of O2 occupies a volume of 5.0 L at a particular temperature and pressure, what volume will 3.00 moles of oxygen gas occupy under the same condition?

Answer 1

Answer: Volume occupied by 3.00 moles of oxygen gas under the same condition is 3.75 L.

Explanation:

Given: $n_{1}$ = 4.00 moles,          $V_{1}$ = 5.0 L

$n_{2}$ = 3.00 moles,                 $V_{2}$ = ?

Formula used is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{5.0 L}{4.00 mol} = \frac{V_{2}}{3.00 mol}\\V_{2} = 3.75 L$

Thus, we can conclude that volume occupied by 3.00 moles of oxygen gas under the same condition is 3.75 L.