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natka813 [3]
3 years ago
11

Please Help me it's my last question I need ​

Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0

Answer:

it would be A if i did my stuff right but make sure that you check online for this stuff to in case i am wrong

Step-by-step explanation:

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What's 5 - the square root of x + 10 = the square root of 7 - x
Tcecarenko [31]
\bf 5-\sqrt{x+10}=\sqrt{7-x}\impliedby \textit{squaring both sides}
\\\\\\
(5-\sqrt{x+10})^2=(\sqrt{7-x})^2
\\\\\\
(5^2)-10\sqrt{x+10}+(x+10)=7-x
\\\\\\
35-10\sqrt{x+10}+x=7-x\implies 28-10\sqrt{x+10}+2x=0
\\\\\\
2x+28=10\sqrt{x+10}\implies x+14=5\sqrt{x+10}\impliedby 
\begin{array}{llll}
squaring\ both\\
sides\ again
\end{array}
\\\\\\


\bf (x^2)+28x+(14^2)=5^2(x+10)\implies x^2+28x+196=25x+250
\\\\\\
\begin{array}{lcclll}
x^2&+3x&-54&=0\\
&\uparrow &\uparrow \\
&-6+9&-6\cdot 9
\end{array} \implies (x+9)(x-6)=0\implies 
\begin{cases}
x+9=0\\
\boxed{x=-9}\\
-----\\
x-6=0\\
\boxed{x=6}
\end{cases}
3 0
3 years ago
Romeo draws a marble from the jar ,does not replace it then flips a coin
Roman55 [17]

Answer:

Independent.

Explanation:

First, Romeo draws a marble from the jar and does not replace it.

Next, he flips a coin.

The outcome from the second event is not affected by the event of picking a marble.

Therefore, the two events are Independent.

4 0
1 year ago
NEED HELP IN MATH .THANKS
stira [4]
It's simple. as long as it's a 10 you just put in however many 0 it has as the root to a 1. or just multiply it however many times.
10x10x10 = 1000
so 10^3 = 1000
then you finish
4.23 x 1000 = 4230
6 0
3 years ago
Which expressions are equivalent<br> to 1/81 ? check all that apply.<br> picture provided
Taya2010 [7]

{8}^{ - 1}  =  \frac{1}{8}

8-¹ ❌

{9}^{ - 2}  =  \frac{1}{ {9}^{2} }  =  \frac{1}{81}

9-² ✔️

\frac{ {9}^{8} }{ {9}^{4} }  =  {9}^{8 - 4}  =  {9}^{8}

9^8/9^4 ❌

\frac{9 {}^{8} }{ {9}^{10} }  =  {9}^{8 - 10}  =  {9}^{ - 2}  =  \frac{1}{9 {}^{2} }  =  \frac{1}{81}

9^8/9^10 ✔️

{9}^{ - 6}  \times  {9}^{3}  =  {9}^{ - 6 + 3}  =  {9}^{ - 3}  =  \frac{1}{9 {}^{3} }  =  \frac{1}{729}

9^-6 . 9³ ❌

{9}^{5} . \:  { 9}^{ - 7}  =  {9}^{5 - 7}  = 9 {}^{ - 2}  =  \frac{1}{ {9}^{2} }  =  \frac{1}{81}

9^5 . 9^-7 ✔️

4 0
3 years ago
Find the quotient -7 divided by 14/3
Brrunno [24]
-7:\frac{14}{3}=-7\times\frac{3}{14}=-\frac{7}{1}\times\frac{3}{14}=-\frac{\not7^1\times3}{1\times\not14_2}=-\frac{1\times3}{1\times2}=-\frac{3}{2}\\\\=-\frac{2+1}{2}=\huge\boxed{-1\frac{1}{2}}
4 0
3 years ago
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