To find first term, you need substitute
n=1
<span>a(n)=1+(n-1)(5.7)
</span>a(1)= 1+(1-1)(5.7)=1
a(1) =1
Fourth term,
n=4
a(4)=1+(4-1)(5.7)
a(4) = 18.1
For 10th term,
n=10
a(10)=1+(10-1)(5.7)=52.3
bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
<span>
Higher
Order Thinking problems require you to think about the facts that are
given to you in any problem and do something with those facts. This
involves understanding them, infer from them, connect them to other
facts and concepts, categorize them, manipulate them, put them
together and apply them to find new solutions.
<span>
For
example the first problem which asks to evaluate the expression
0.1(3.7). This can also mean that 1/10*3.7 = 0.37.
I hope
it helps, Regards.</span></span>
(((x + y) / 3) + (1 / x)) / (5 + (15 / x))
The best way is to make it one fraction.
Multiply by ((3x/3x) / (3x/3x)) to remove the other fractions.
((x(x + y)) + 3(1)) / (5(3x) + 3(15))
(x^2 + xy + 3) / (15x + 45)
Then factor to simplify
(x^2 + xy + 3) / (3(x + 15))
