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2 years ago

Enter the unknown number for n. 12.66 − n = 7.64 Brainliest..........

Mathematics

2 answers:

Gemiola [76]2 years ago

5 0

Answer:

Step-by-step explanation:

12.66-n=7.64

12.66-7.64=n

5.02=n

n200080 [17]2 years ago

5 0

5.02 just subtract 7.64 from 12.66 :)

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The tangents to the curve with equation y = x^3-3x at the points A and B with x coordinates −1 and 4 respectively meet at the po

sladkih [1.3K]

Answer:

$\displaystyle C=\left(\frac{26}{9}, 2\right)$

Step-by-step explanation:

We need to find the equation of the tangent lines of Points A and B.

Differentiate the equation:

$\displaystyle \frac{dy}{dx}=3x^2-3$

Point A has an x-coordinate of -1. Hence, the slope of its tangent line is:

$\displaystyle \frac{dy}{dx}\Big|_{x=-1}=3(-1)^2-3=0$

Find the y-coordinate of Point A using the original equation:

$y(-1)=(-1)^3-3(-1)=2$

Hence, Point A is (-1, 2).

Thus, the tangent line at Point A is:

$y-2=0(x-(-1))$

Simplify:

$y=2$

Point B has an x-coordinate of 4. Hence, the slope of its tangent line is:

$\displaystyle \frac{dy}{dx}\Big|_{x=4}=3(4)^2-3=45$

Find the y-coordinate of Point B:

$y(4)=(4)^3-3(4)=52$

Thus, Point B is at (4, 52).

So, the tangent line at Point B is:

$y-52=45(x-4)$

Simplify:

$y=45x-128$

Point C occurs at the intersections of the tangent lines of Points A and B. Set the two equations equal to each other and solve for x:

$2=45x-128$

We acquire:

$\displaystyle x=\frac{26}{9}$

Since one of our equations is y = 2, the y-coordinate is 2.

Hence, Point C is:

$\displaystyle C=\left(\frac{26}{9}, 2\right)$

5 0

2 years ago

Read 2 more answers

Explain how to perform a two-sample z-test for the difference between two population proportions.

Sati [7]

Point estimate for the difference between two population proportions is the difference between the two sample proportions, written as:

$\hat{p}_1-\hat{p}_2$

and the standard deviation is given by

$\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}$

When np and n(1-p) is greater than 5, then the sampling distribution is approximately normal and we can use standard normal methods.

Thus, the propability of a test for the difference between two population proportions is given by

$P(X\ \textless \ x)=P\left(z\ \textless \ \frac{\hat{p}_1-\hat{p}_2}{\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}} \right)$