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jasenka [17]
3 years ago
9

If you want to adjust the width of a column manually, move your mouse over the _______ column boundary and click and drag until

the column is the size you want.
Computers and Technology
1 answer:
Luda [366]3 years ago
6 0

Answer:

The answer is "Right".

Explanation:

In computer science, editing is the primary activity, which is used by the users to handles graphics, tables, and other things. It can be divided into two types first is internal(default) and the second is manual.

  • In the manual editing, to edit the column of the table we just right click on the column.
  • It enables you to edit option, in which we edit column according to our desire.
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45 points pls help
Artemon [7]

Answer:

Repetition.

Explanation:

hope it helps u

can u mark me as brainliest

8 0
3 years ago
Read 2 more answers
Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.
Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

v = \frac{(xf-xo)}{(t-to)}

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

t =\frac{xf}{v}  =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.

⇒ t = 8.7*10⁻⁴ sec.

4 0
3 years ago
1st row has 3 possible answers software program, web page, and web browser
Maurinko [17]

Answer:

1st row: software program

2nd row: a user's computer

hope i've helped.

7 0
3 years ago
The purpose of this assignment is to determine a set of test cases knowing only the function’s specifications, reported hereaf
Nesterboy [21]

Answer:

The program is written using PYTHON SCRIPT below;

N=int(input(" Enter number of Rows you want:"))

M=[] # this for storing the matrix

for i in range(N):

l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))

M.append(l)

print("The 2D Matrix is:\n")

for i in range(N):

print(end="\t")

print(M[i])

W=[] # to store the first non zero elemnt index

T=[] # to store that value is positive or negative

L=len(M[0])

for i in range(N):

for j in range(L):

if (M[i][j]==0):

continue

else:

W.append(j) # If the value is non zero append that postion to position list(W)

if(M[i][j]>0): #For checking it is positive or negative

T.append(+1)

else:

T.append(-1)

break

print()

print("The first Non Zero element List [W] : ",end="")

print(W)

print("Positive or Negative List [T] : ",end="")

print(T)

Explanation:

In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.

It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.

5 0
3 years ago
- Create a Java program in both Windows and Ubuntu using any of their Editors *** DO NOT USE IDE'S SUCH AS ECLIPSE, NETBEANS, ET
Marat540 [252]

Answer:

Following are the code to this question:

public class ArrayMath//defining a class ArrayMath

{

public static void main(String[] args) //defining main method

{

int x[][]=new int[10][10]; //defining a 2D array  

arrays(x);//calling a method arrays by passing an array

}

private static void arrays(int[][] x)//defining a method arrays

{

int odd_column_sum=0,sum_of_Elements=0,i,j,even=1;//defining integer variable  

for(i=0;i<x.length;i++)//defining loop for columns  

{

for(j=0;j<x[0].length;j++)//defining loop for rows

{

x[i][j]=i*j;//multiply the i and j value atore in array

}

}

System.out.println("::The 2D array :: ");//print message

for(i=0;i<x.length;i++)//defining loop for columns

{

System.out.print("\t");//use print method for line space and line break  

for(j=0;j<x[0].length;j++)//defining loop for rows

{

System.out.printf("%d\t",x[i][j]); //print array values

}

System.out.println( );//print for line break

}

for(i=0;i<x.length;i++) //defining loop for Columns

{

for(j=0;j<x[0].length;j++) //defining loop for rows

{

if(even%2!=0)//defining if block for check odd number condition

{

odd_column_sum+=x[j][i];//add odd number of array

}

sum_of_Elements+=x[i][j];//add even number of array

}

even++;//increment even variable value by 1

}

System.out.println("The sum of Odd Columns:"+odd_column_sum);//print odd_column_sum value

System.out.println("The array elements :"+sum_of_Elements);//print sum_of_Elements value

}

}

Output:

please find attached file.

Explanation:

In the above-given code, a class "ArrayMath" is defined, inside the class the main method is declared, which define a 2D array "x", this stores 10 columns and 10 rows and at the last, we call the arrays method by passing an array as a variable.

In the arrays method, integer variable, "odd_column_sum, sum_of_Elements, i, j, and even" is defined, in which variable "i and j" is used in the loop for calculating value, even is used to check odd column and then store its value in the "odd_column_sum" variable, and add whole element value is added into the "sum_of_Elements" variable.

8 0
3 years ago
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