Question

What is the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH in the following chemical reaction? 2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)

Answer 1

Answer:

69.6 g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams LiOH to moles LiOH (via molar mass from periodic table values), then (2) convert moles LiOH to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (desired unit in the numerator). The final answer should have 3 sig figs to reflect the given value's sig figs.

Molar Mass (LiOH): 6.9410 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (LiOH): 23.947 g/mol

2 LiOH(s) + 1 CO₂(g) ----> Li₂CO₃(s) + H₂O(l)

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

75.8 g LiOH          1 mole             1 mole CO₂               44.007 g
------------------  x  ----------------  x  -----------------------  x  -------------------  =
                            23.947 g         2 moles LiOH              1 mole

= 69.6 g CO₂