(10.0 g Al2(SO3)3) / (294.1544 g Al2(SO3)3/mol) = 0.033996 mol Al2(SO3)3 (10.0 g NaOH) / (39.99715 g NaOH/mol) = 0.25002 mol NaOH
0.033996 mole of Al2(SO3)3 would react completely with 0.033996 x (6/1) = 0.203976 mole of NaOH, but there is more NaOH present than that, so NaOH is in excess and Al2(SO3)3 is the limiting reactant.
Answer:
0.082L or 82mL
Explanation:
Given parameters:
Pressure of gas = 780mmHg;
760mmHg = 1atm
780mmHg = 
= 1.03atm
Volume of gas = 80ml = 0.08L
Standard pressure = 1atm
Unknown:
Volume of gas = ?
Solution:
To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of gas is inversely proportional to the pressure if the temperature is constant".
Mathematically;
P₁ V₁ = P₂ V₂
P and V are temperature values
1 and 2 are initial and final states;
Insert the parameters and solve;
1.03 x 0.08 = 1 x V₂
V₂ = 0.082L or 82mL
The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element.
Answer:
378.25°C
Explanation:
Given data:
Number of moles of gas = 0.750 mol
Volume of gas = 35.9 L
Pressure of gas = 114 KPa (114/101 = 1.125 atm)
Temperature of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
now we will put the values.
T = PV/nR
T = 1.125 atm × 35.9 L /0.750 mol × 0.0821 atm.L/ mol.K
T = 40.3875/0.062/K
T = 651.4 K
Kelvin to °C:
651.4 K - 273.15 = 378.25°C
Answer:
A
Explanation:
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