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Shkiper50 [21]
3 years ago
11

I don't unerstand what I'm supposed to do for these

Chemistry
2 answers:
shepuryov [24]3 years ago
8 0
You just need to multiply the terms and transform to kj by dividing by 1000
1) 10.4kj
2) 14.5 kj 
3) 44.8 kj
4) 1.04 kj

and there you go.
Anon25 [30]3 years ago
3 0

Explanation:

1000 J= 1 kJ

1. Heat = mass × c × Temperature change

=175 g\times 0.79 J/g^oC\times 75^oC=10,368.75 J=10.36878 kJ\approx 10.4 kJ

2.Heat = mass × c × Temperature change

=352 g\times 1.65 J/g^oC\times 25^oC=14,520 J=14.520 kJ\approx 14.5 kJ

3.Heat = mass × c × Temperature change

=268 g\times 4.18 J/g^oC\times 40^oC=44,809.6 J=44.8096 kJ\approx 44.8 kJ

4.Heat = mass × c × Temperature change

=74 g\times 0.21 J/g^oC\times 67 ^oC=1,041.18 J=1.04118 kJ\approx 1.04 kJ

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Because the density of water is one

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A chemist prepares a solution of sodium thiosulfate by measuring out of sodium thiosulfate into a volumetric flask and filling t
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Mass of sodium thiosulfate Na_{2}S_{2}O_{3} is 110. g

Volume of the solution is 350. mL

Calculating the moles of sodium thiosulfate:

110. g Na_{2}S_{2}O_{3} * \frac{1 mol Na_{2}S_{2}O_{3}}{158.1 g Na_{2}S_{2}O_{3}} = 0.696 molNa_{2}S_{2}O_{3}

Converting the volume of solution to L:

350. mL * \frac{1 L}{1000 mL} = 0.350 L

Finding out the concentration of solution in molarity:

\frac{0.696 mol}{0.350 L} =  1.99 mol/L

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How many atoms of carbon are represented in 3CH3CH20
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How many moles of Calcium Oxide are needed to produce 4 moles of Calcium Hydroxide?
Tpy6a [65]

Taking into account the reaction stoichiometry, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CaO + H₂O → Ca(OH)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CaO: 1 mole
  • H₂O: 1 mole
  • Ca(OH)₂:  1 mole

<h3>Moles of CaO required</h3>

The following rule of three can be applied: If by stoichiometric reaction 1 mole of Ca(OH)₂ is produced by 1 mole of CaO, 2 moles of Ca(OH)₂ are produced by how many moles of CaO?

moles of CaO=\frac{2 moles of Ca(OH)_{2}x1 mol of CaO }{1 mole of Ca(OH)_{2}}

moles of CaO= 2 moles

Finally, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.

Learn more about the reaction stoichiometry:

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