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Shkiper50 [21]
3 years ago
11

I don't unerstand what I'm supposed to do for these

Chemistry
2 answers:
shepuryov [24]3 years ago
8 0
You just need to multiply the terms and transform to kj by dividing by 1000
1) 10.4kj
2) 14.5 kj 
3) 44.8 kj
4) 1.04 kj

and there you go.
Anon25 [30]3 years ago
3 0

Explanation:

1000 J= 1 kJ

1. Heat = mass × c × Temperature change

=175 g\times 0.79 J/g^oC\times 75^oC=10,368.75 J=10.36878 kJ\approx 10.4 kJ

2.Heat = mass × c × Temperature change

=352 g\times 1.65 J/g^oC\times 25^oC=14,520 J=14.520 kJ\approx 14.5 kJ

3.Heat = mass × c × Temperature change

=268 g\times 4.18 J/g^oC\times 40^oC=44,809.6 J=44.8096 kJ\approx 44.8 kJ

4.Heat = mass × c × Temperature change

=74 g\times 0.21 J/g^oC\times 67 ^oC=1,041.18 J=1.04118 kJ\approx 1.04 kJ

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Answer:

(a) the mass of the water is 3704 g

(b) the mass of the water is 199, 285.7 g

Explanation:

Given;

Quantity of heat, H= 8.37 x 10⁶ J

Part (a) mass of water (as sweat) need to evaporate to cool that person off

Latent heat of vaporization of water, Lvap. = 2.26 x 10⁶ J/kg

H = m x Lvap.

m = \frac{H}{L._{vap}} =\frac{8.37 * 10^6.J}{2.26*10^6\ \frac{J}{kg}} = 3.704 \ kg

mass in gram ⇒ 3.704 kg x 1000g = 3704 g

Part (b) quantity of water raised from 25.0 °C to 35.0 °C by 8.37 x 10⁶ J

specific heat capacity of water, C, 4200 J/kg.°C

H = mcΔθ

where;

Δθ is the change in temperature = 35 - 25 = 10°C

m =\frac{H}{c* \delta \theta} = \frac{8.37 *10^6}{4200*10} = 199.2857 kg

mass in gram ⇒ 199.2857 kg x 1000 g = 199285.7 g

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