Im thinking 10 because 10+40=50 and 10x7=70
4x + 15 = 6x - 1
x = 8
m∠JLC = 47°
Answer:
The distance between 12m-sides is
.
Step-by-step explanation:
It is given that the parallelogram has sides 10m and 12m and an angle of 45°.
Draw an altitude from one 12m side to another 12 m side as shown in below figure.
The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.
Since angle C is acute angle therefore it must be 45 degree.








Therefore the distance between 12m-sides is
.
Box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. The key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.