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Art [367]
3 years ago
10

What steps would you take to determine if these figures are similar? 

Mathematics
2 answers:
Alla [95]3 years ago
4 0
What figures are there
Dimas [21]3 years ago
3 0

Answer:the answers are B.Multiply the vertices of polygon ABCD by 1/2 and E.Reflect the intermediate image

Step-by-step explanation:

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The right answer is 50% .
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The table of values represents a quadratic function. What is the average rate of change for f(x) from x = 0 to x = 10 ? Enter yo
Elena-2011 [213]
By definition we have that the average rate of change is given by:
 AVR = (f (x2) - f (x1)) / (x2 - x1)
 Substituting the values we have:
 AVR = (204 - (-6)) / (10 - 0)
 Rewriting we have:
 AVR = (204 + 6) / (10 - 0)
 AVR = 210/10
 AVR = 21
 Answer:
 
the average rate of change for f (x) from x = 0 to x = 10 is:
 
AVR = 21
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4 years ago
What are the coordinates of the image of the point (2, –6) under a dilation with a center of (0, 0) and a scale factor of 1/2
ycow [4]

That would be (1, -3) because you basically divide the coordinates by the scale factor, in this case 2.

8 0
3 years ago
How do I write 208,000,478 in expanded form
Rama09 [41]

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4 0
3 years ago
Read 2 more answers
Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the fiv
Dahasolnce [82]

Answer and Explanation:

Given : Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the​ X-linked genetic disorder.

To find :

a. Does the table show a probability distribution?

b. Find the mean and standard deviation of the random variable x.

Solution :

a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.029+0.147+0.324+0.324+0.147+0.029

\sum P(X)=1

Yes it is a probability distribution.

b) First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.029         0              0                0

1     0.147        0.147           1              0.147

2    0.324       0.648         4              1.296

3    0.324       0.972         9              2.916

4    0.147        0.588        16              2.352

5    0.029       0.145         25            0.725

   ∑P(x)=1      ∑xP(x)=2.5               ∑x²P(x)=7.436

The mean of the random variable is

\mu=\sum xP(x)=2.5

The standard deviation of the random sample is

Variance=\sigma^2

\sigma^2=\sum x^2P(x)-\mu^2

\sigma^2=7.436-(2.5)^2

\sigma^2=7.436-6.25

\sigma^2=1.186

\sigma=\sqrt{1.186}

\sigma=1.08

Therefore, The mean is 2.5 and the standard deviation is 1.08.

5 0
3 years ago
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