1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhuklara [117]
3 years ago
13

A 25 pF parallel-plate capacitor with an air gap between the plates is connected to a 100 V battery. A Teflon slab (dielectric c

onstant 2.0) is then inserted between the plates, and completely fills the gap.
(a) What is the change in the charge on the positive plate when the Teflon is inserted?
Physics
1 answer:
adoni [48]3 years ago
3 0

Answer:

The change in the charge on the positve plate when the Teflon is inserted is +2.5 nC.

Explanation:

  • It can be showed that the capacitance of a parallel-plate capacitor, can be expresssed as follows:

       C = \frac{\epsilon*A}{d}

  • Where ε, is the dielectric constant of the material that fills the space between plates.
  • When this space is filled with air, ε= ε₀ = 8,85*10⁻¹² F/m.
  • At the same time, the capacitance of a capacitor, by definition, is as follows:

       C =\frac{Q}{V}

  • If we insert a Teflon slab, in such a way that fills completely the gap between the plates, all other parameters being equal, if ε = 2*ε₀, this means that C₂ = 2* C₁. = 50 pF
  • As V₂=V₁ (due to the capacitor remains connected to the same battery) the charge must be the double, so Q₂ = 2* Q₁ = 5 nC.
  • So, the change in the charge of the positive plate is +2.5 nC.
You might be interested in
Is the process of changing from one phase of matter to another a physical change or a chemical change? Explain why. please asap
Andreas93 [3]

The process of changing from one phase  of matter to another is a physical matter.

7 0
3 years ago
If an object absorbs all colors but red, we see
julia-pushkina [17]
[I researched for you, since I am not in that particular level to know that knowledge yet. I assure this is accurate info :)]

The answer is A, red.
"Remember, the color you see is light REFLECTING off the surface of that object. If all colors are absorbed in to the surface EXCEPT red, red must be reflected, and you'll see red." - Yahoo User @Chap
8 0
3 years ago
WEATHER: <br> What kind of weather occurs along this type of front?
Radda [10]
Cold front because the warm front or hit front is lower on the right and goes downwards and cold front is in the middle and goes to Minneapolis
4 0
2 years ago
Read 2 more answers
An electron in a vacuum is first accelerated by a voltage of 51400 V and then enters a region in which there is a uniform magnet
zimovet [89]

Answer:

       F = 8.6 10⁻¹² N

Explanation:

For this exercise we use the law of conservation of energy

Initial. Field energy with the electron at rest

         Em₀ = U = q ΔV

Final. Electron with velocity, just out of the electric field

         Emf = K = ½ m v²

          Em₀ = Emf

          e ΔV = ½ m v²

          v =√ 2 e ΔV / m

          v = √(2 1.6 10⁻¹⁹ 51400 / 9.1 10⁻³¹)

           v = √(1.8075 10¹⁶)

           v = 1,344 10⁸ m / s

Now we can use the equation of the magnetic force

         F = q v x B

Since the speed and the magnetic field are perpendicular the force that

        F = e v B

        F = 1.6 10⁻¹⁹  1.344 10⁸ 0.4

       For this exercise we use the law of conservation of energy

Initial. Field energy with the electron at rest

         Emo = U = q DV

Final. Electron with velocity, just out of the electric field

         Emf = K = ½ m v2

          Emo = Emf

          .e DV = ½ m v2

          .v = RA 2 e DV / m

          .v = RA (2 1.6 10-19 51400 / 9.1 10-31)

           .v = RA (1.8075 10 16)

           .v = 1,344 108 m / s

Now we can use the equation of the magnetic force

         F = q v x B

Since the speed and the magnetic field are perpendicular the force that

        F = e v B

       F = 1.6 10-19 1,344 108 0.4

       F = 8.6 10-12 N

5 0
2 years ago
A 65-kg ice skater stands facing a wall with his arms bent and then pushes away from the wall by straightening his arms. At the
Marrrta [24]

Our values can be defined like this,

m = 65kg

v = 3.5m / s

d = 0.55m

The problem can be solved for part A, through the Work Theorem that says the following,

W = \Delta KE

Where

KE = Kinetic energy,

Given things like that and replacing we have that the work is given by

W = Fd

and kinetic energy by

\frac {1} {2} mv ^ 2

So,

Fd = \frac {1} {2} m ^ 2

Clearing F,

F = \frac {mv ^ 2} {2d}

Replacing the values

F = \frac {(65) (3.5)} {2 * 0.55}

F = 723.9N

B) The work done by the wall is zero since there was no displacement of the wall, that is d = 0.

6 0
2 years ago
Other questions:
  • A traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south. Find the traveler's total displacement
    14·1 answer
  • Three identical 6.0-kg cubes are placed on a horizontal frictionless surface in contact with one another. The cubes are lined up
    5·1 answer
  • Compare the kinetic energy of a 20,000-kg truck moving at 110 km/h with that of an 80.0-kg astronaut in orbit moving at 27,500 k
    5·1 answer
  • A piece of solid copper, at 10oC, is dropped into a graduated cylinder of 100°C water. Which statement BEST describes the change
    10·2 answers
  • What was one of the main benefits to the use of the icebox for cooling food? Select all that apply. provided a source for cold w
    5·2 answers
  • This ray diagram shows the image formed when a candle is placed in front of
    15·1 answer
  • Compare and contrast chemical reactions and nuclear reactions in terms of particles involved . Select all the statements that ap
    8·1 answer
  • A ride at an amusement park attaches people to a bungee cord, pulls them
    8·1 answer
  • The force required to maintain an object at a constant velocity in free space is equal to what ?
    5·1 answer
  • A test charge gains 10 joules of potential energy as it moves through an electric field. It starts its movement at point 1 and e
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!