m = mass of the circular hoop
r = radius of the hoop
I = moment of inertia of the hoop
moment of inertia of the hoop about the center of hoop is given as
I = m r²
k = distance of the point of suspension from center of mass = r
using parallel axis theorem
I' = moment of inertia of hoop about the point of suspension
I' = I + m k²
I' = m r² + m k²
I' = m r² + m r²
I' = 2 m r²
Time period of oscillation for the hoop is given as
T = 2π sqrt(I'/mgk)
T = 2π sqrt(2 m r²/(mgr))
T = 2π sqrt(2 r/g)
since 2r = diameter = d
T = 2π sqrt(d/g)
You have three known variables:
Acceleration -
Time -
Initial Velocity -
For the first part of your question:
For the second part of your question:
This still needs to be converted to m/h:
According to Coulomb's Law. T<span>he relationship between the electric force between two charged objects and the distance between them is:
F = 1/d^2
So,
</span><span>As the distance increases by a factor, the electric force decreases by the square of that factor.</span>
0.05*0.2=0.05*0.15+0.015*m2',
m2'=1/6 m/s,
m2'=0.17 m/s
N I C E - D A Y!