11 cubic feet is the answer
Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
Answer:
Looks like <u>inverse property of addition </u>to me
Answer:
see below
Step-by-step explanation:
Plot the points on the given graph. The ones that fall in on a solid line at the edge of the doubly-shaded area, or fall in the doubly-shaded area, are part of the solution set.
(0, 4) on the dashed line — not a solution
(-2, 4) on red line in blue area — solution
(0, 5) in doubly-shaded area — solution
(–2, 7) in doubly-shaded area — solution
(–4, 1) in blue area — not a solution
(–1, 1) on red line outside blue area — not a solution
(–1.5, 3.5) in doubly-shaded area — solution
