Answer:
Step-by-step explanation:
Which is the last operation performed when evaluating (8 minus 2 x) squared + 4 for x = 3?
1 answer:
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Answer:
= 2
= k(k+1)
= (k+1)(k+2)
Step-by-step explanation:
We are given the statement,
as 2 + 4 + 6 + . . . + 2n = n(n+1)
That is,
as 2 + 4 + 6 + . . . + 2n =
So, we have,
=
= 2
=
= 2 + 4 + 6 + . . . + 2k = k(k+1)
=
= 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)
Thus, we get,
= 2
= k(k+1)
= (k+1)(k+2)
y - y₁ = m(x - x₁)
y - 4 = 1(x - 3)
y - 4 = 1(x) - 1(3)
y - 4 = x - 3
+ 4 + 4
y = x + 1
